Maharashtra Board Class 6 Math Chapter 13 Profit Loss Solution

Maharashtra Board Class 6 Math Solution Chapter 13 – Profit Loss

Balbharati Maharashtra Board Class 6 Math Solution Chapter 13: Profit Loss. Marathi or English Medium Students of Class 6 get here Profit Loss  full Exercise Solution.

Std

Maharashtra Class 6
Subject

Mathematics Solution

Chapter

Profit Loss

(1) CP = Rs. 4500; SP = Rs. 5000

Therefore, Profit = SP – CP = Rs (5000-4500)

How much = Rs 500

(2) CP = Rs 4100; SP = Rs. 4090

Therefore, Loss= (CP-Sp) = Rs ( 4100-4090)

=Rs 10

(3) CP = Rs. 700;                SP = Rs 799

Therefore, Profit= SP – CP = Rs (799-700)

= Rs 99

(4)  CP= Rs1000; SP=Rs 920

Therefore, Loss= CP-SP = Rs (1000-920)

= Rs 80

(2.) A shopkeeper bought a bicycle for Rs. 3000 and sold the same for Rs. 3400.
How much was his profit?

Solution: CP of bicycle = Rs 3000

Sp of bicycle = Rs 3400

Therefore, Profit= Rs (3400-3000)

= Rs 400

(3) Sunandabai bought milk for Rs. 475. She converted it into yoghurt and sold it for Rs. 700. How much profit did she make?

Solution: CP of milk = Rs 475

SP of yoghurt = Rs 700

Therefore, Profit = Rs (700-475)

= Rs 225

(4) The Jijamata Women’s Saving Group bought raw materials worth Rs. 15000 for making chakalis. They sold the chakalis for 22050 rupees. How much profit did the WSG make?

Solution: CP of materials =Rs 15000

SP of Chakalis = Rs 22050

Therefore, Profit = Rs (22050-15000)

= Rs 7050

(5) Pramod bought 100 bunches of methi greens for ` 400. In a sudden downpour, 30 of the bunches on his handcart got spoilt. He sold the rest at the rate of ` 5 each. Did he make a profit or a loss? How much?

Solution: Tromod bought 100 bunches for Rs 400

Therefore, Tromod bought 1 bunches for Rs 400/100

= Rs 4

No of spoilt bunches = 30

Therefore, CP of (100-30) = 70 bunches   = Rs (70×4)

= Rs 280

Therefore, Hence, Promod bought nest bunches for Rs 5.

So, Sp of 70 bunches      = Rs (70×5)

= Rs 350

Therefore, Loss = Rs (400-350) = Rs 50

(6) Sharad bought one quintal of onions for Rs. 2000. Later he sold them all at the rate of Rs. 18 per kg. Did he make a profit or incur a loss? How much was it?

Solution: CP of one Quintal of onions = Rs 2000

SP of one quintal of onions = Rs (18×100)

[One quintel = 100 kg]        = Rs 1800

Therefore, Loss = Rs (2000 – 1800) = Rs 200

(7) Kantabai bought 25 saris from a wholesale merchant for Rs. 10000 and sold them all at Rs. 460 each. How much profit did Kantabai get in this transaction?

Solution: CP of 25 saris = Rs 10,000

Sp of 25 saris = Rs (460×25)

= Rs 11,500

Therefore, Profit = Rs (11,500- 10,000)

= Rs 1500

Practice Set 32

(1) From a wholesaler, Santosh bought 400 eggs for Rs. 1500 and spent Rs. 300 on transport. 50 eggs fell down and broke. He sold the rest at Rs. 5 each. Did he make a profit or a loss? How much?

Solution: Santosh apent for 400 eggs = Rs (1500+300)
= Rs 1800
Now, we let the CP of egg = Rs 1800
SP of the eggs = (400-50) = 350 egg
= Rs 1750
Therefore, Santosh loss = Rs (1800 – 1750)
= Rs 50

(2) Abraham bought goods worth Rs. 50000 and spent Rs. 7000 on transport and octroi. If he sold the goods for Rs. 65000, did he make a profit or a loss? How much?

Solution: Abraham spent for goods = Rs (50000 +7000)

SP of the goods = Rs 65000

Therefore, Profit = Rs (65000-57000)

= Rs 8000

(3) Ajit Kaur bought a 50 kg sack of sugar for Rs. 1750, but as sugar prices fell she had to sell it at Rs. 32 per kg. How much loss did she incur?

Solution: CP of 50 kg Sugar = Rs1750

SP of 50 kg Sugar = Rs (50×32)

= Rs 1600

Therefore, Loss = Rs (1750-1600) = Rs 150

(4) Kusumtai bought 80 cookers at Rs. 700 each. Transport cost her Rs. 1280. If she wants a profit of Rs. 18000, what should be the selling price per cooker?

Solution: CP of 80 cookers = Rs (700×80)

= 56000

Spent for transport = Rs 1280

Therefore, total CP of 80 cookers = Rs (56000+1280)

= Rs 57280

Of Kusumtal profit Rs 18000

Therefore, her SP of 80 cookers will

= Rs (57280+18000)

= Rs 75280

Now, Sp of each cooker is = Rs 75280/80

= Rs 941

(5) Indrajit bought 10 refrigerators at Rs. 12000 each and spent Rs. 5000 on transport. For how much should he sell each refrigerator in order to make a profit of Rs. 20000?

Solution: CP of 10 refrigerators = RS (12000×10)

Chandrajit spent money for transport = Rs 5000

Therefore, Ttal CP which we let for CP = Rs (120000+5000)

= Rs 125000

If he want a profit of Rs 20,000

There, His SP will be = RS (125000+20000)

= Rs 145000

Therefore, SP of each refrigerator = Rs 145000/10

= Rs 14500

(6) Lalitabai sowed seeds worth Rs. 13700 in her field. She had to spend Rs. 5300 on fertilizers and spraying pesticides and Rs. 7160 on labour. If, on selling her produce, she earned Rs. 35400 what was her profit or her loss?

Solution: Lalitabari spent total money for her field = Rs (13700+5300+7160)

= Rs 26160

She selling her produce = Rs 35400

Therefore, She Profit = Rs (35400-26160)

= Rs 9240

Practice Set 33 Solution

(1) Solution: CP of trousers = Rs 400
Sp of trousers = Rs 448
Therefore, Profit= Rs (448-400) = Rs 48
CP of shirt = Rs 200
SP of shirt = Rs 250
Therefore, Profit = Rs (250-200) = Rs 50
Hence, Shirt transaction was more profitable

(2) Solution: Ramrao,
CP of cupboard = Rs 4500
SP of cupboard = Rs 4950
Therefore, Profit= Rs (450-4500) = Rs 4500
Shamrao,
CP of sewing machine = Rs 3500
SP of sewing machine = Rs 3920
Therefore, Profit = Rs (3920-3500) = Rs 420
Hence, Ramrao’s transaction was more profitable

(3) Solution : CP of Apples = Rs 400
SP of 50 Apples = Rs (50×10)
=Rs 500
Therefore, Profit = Rs (500-400) = Rs 100
Percentage = (Profit/CP x100) %
= (100/400×100) %
25%

Practice Set 34 Solution

(1) Cost price Rs. 1600, selling price Rs. 2800.

Solution: CP = Rs 1600 SP = Rs 2800
Profit = Rs (2800-1600) =Rs 1200
Therefore, Percentage = (1200/1600×100) % = 75%

(2) Cost price Rs. 2000, selling price Rs. 1900.

Solution: CP = Rs 2000 SP = 1900
Loss = Rs (2000-1900) = Rs 100
Therefore, Percentage = (100/2000×100) %
=5%

(3) Cost price of 8 articles is Rs. 1200 each, selling price Rs. 1400 each.

Solution: CP of 8 Articles = Rs (1200×8) = Rs 9600
SP of 8 Articles = Rs (1400×8)
Therefore, Profit = Rs (11200-9600)
=Rs 1600
Therefore, Percentage = (1600/9600×100) %
=50/3 %

(4) Cost price of 50kg grain Rs. 2000, Selling price Rs. 43 per kg.

Solution: CP of 50 kg grain = Rs 2000
SP of 50 kg grain = Rs (43×50)
=Rs 2150

Therefore, Profit = Rs (2150- 2000)

Therefore, Percentage
= Rs 150 =(150/2000×100) %
= 15/2%

(5) Cost price Rs. 8600,
transport charges Rs. 250,
porterage Rs. 150,
selling price Rs. 10000

Solution: CP = Rs 8600
Transport charges = Rs 250
Porte rage = Rs 150
Therefore, Total spent money = Rs (8600+250+150)
= Rs 9000
SP = Rs 10,000
Therefore, Profit = Rs (10000-9000) = Rs 1000
Therefore, Percentage = (1000/9000 x 100) %
= 100/9 %

(6) Seeds worth Rs. 20500,
labour Rs. 9700,
chemicals and fertilizers Rs. 5600,
selling price Rs. 28640.

Solution: Seeds worth = Rs 20500
Labours = Rs 9700
Chemical and fertilizers = Rs 5600
Therefore, CP = Rs (20500+9700+5600)
= Rs 35800
Therefore, SP = Rs (28640
Therefore, Loss = Rs (35800-28640)
= Rs 7160
Therefore, Percentage = (7160/35800 x 100) % = 20%

Updated: July 30, 2022 — 1:58 pm

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