Maharashtra Board Class 5 Math Solution Chapter 2 – Number Work
Balbharati Maharashtra Board Class 5 Math Solution Chapter 2: Number Work. Marathi or English Medium Students of Class 5 get here Number Work full Exercise Solution.
Std | Maharashtra Class 5 |
Subject | Mathematics Solution |
Chapter | Number Work |
Problem Set 2
(1)Using the digits 0, 1, 2, 3, 4, 5, 6, 7, 8, 9 write ten each of two-, three-, four- and five-digit numbers. Read the numbers.
Solution:
Ten two digit number: 10, 11, 12, 13, 14, 15, 16, 17, 18, 19
Ten three digit number: 100, 101, 102, 103, 104, 105, 106, 107, 108, 109
Ten four digit number – 1000, 1001, 1002, 1003, 1004, 1005, 1006, 1007, 1008, 1009
Ten Five digit number – 10000, 10001, 10002, 10003, 10004, 10005, 10006, 10007, 10008, 10009
(2) Fill in the blanks in the table below.
Devanagari Numerals | International Numerals | Number written in words |
(1) २,३५९ | 2,359 | Two thousand, three hundred and fifty-nine |
(2) ३२,७५६ | 32,756 | Thirty two thousand, seven hundred and fifty-six
|
(3) ६७,८५९ | 67,859 | Sixty seven thousand, eight hundred and fifty-nine
|
(4) १,०३४ | 1,034 | One thousand and thirty-four |
(5) २७,८९५ | 27,895 | Twenty-seven thousand, eight hundred and ninety-five |
(3) As a part of the ‘Avoid Plastic Project’, Zilla Parishad schools made and provided paper bags to provision stores and greengrocers. Read the talukawise numbers of the bags and
write the numbers in words.
Kopargaon 12,740 Twelve thousand, seven hundred and forty
Shevgaon 28,095 Twenty thousand and ninety-five
Karjat 31,608 Thirty one thousand, six hundred and eight
Sangamner 10,972 Ten thousand nine hundred and seventy-two
(4) How many rupees do they make ?
1.) 20 notes of 1000 rupees, 5 notes of 100 rupees and 14 notes of 10 rupees.
Twenty thousand six hundred and forty rupees
Explanation:
20 notes of 1000 rupees = 20 x 1000 = 20,000
5 notes of 100 rupees = 5 x 100 = 500
14 notes of 10 rupees = 14 x 10 = 140
So, in total = 20,000 + 500 + 150 = 20,640
2.)15 notes of 1000 rupees, 12 notes of 100 rupees, 8 notes of 10 rupees and 5 coins of 1 rupee.
Sixteen thousand two hundred and eighty five rupees
Explanation:
15 notes of 1000 rupees = 15 x 1000 = 15,000
12 notes of 100 rupees = 12 x 100 = 1200
8 notes of 10 rupees = 8 x 10 = 80
5 coins of 1 rupee = 5 x 1 = 5
So, in total = 15,000 + 1200 + 80 + 5 = 16285
(5)Write the biggest and the smallest five-digit numbers that can be made using the digits
4, 5, 0, 3, 7 only once.
Biggest 75,430
Smallest 30,457
(6) The names of some places and their populations are given below. Use this information to answer the questions that follow.
1.) Washi has the greatest population. Its population is 92,173.
2.) Moregaon has greater population.
3.) Bhamragad has smallest population. It is 35,390.
PROBLEM SET 3
1.) Read the numbers and write them in words
(1) Seven lakh, sixty five thousand, two hundred and thirty-five
(2) Four lakh, seventy-three thousand, two hundred and twenty-five
(3) Three lakh, twenty-seven thousand and one.
(4) Eight lakh, seventy-five thousand, three hundred and seventy-five.
(5) One lakh, fifty thousand, four hundred and thirty seven.
(6) Two lakh, three thousand, one hundred and seventy four.
(7) Six lakh, forty-seven thousand, eight hundred and fifty-one.
(8) Nine lakh, nine hundred and ninety-nine.
(9) Five lakh, seventy-five thousand and ten.
(10) Four lakh, three thousand and five.
2.) Read the numbers and write them in figures.
(1) 1,35,855
(2) 7,27000
(3) 4,25,300
(4) 9,09,099
(5) 7,49,362
(6) 8,00,000
3.) Make five six-digit numbers, each time using any of the digits 0 to 9 only once.
1,23,456
4,56,789
7,85,432
1,02,657
3,21,456
PROBLEM SET 4
1.) Read the numbers and write them in words
(1) Twenty-five lakh, seventy-nine, eight hundred and ninety-nine
(2) Thirty lakh, seventy thousand, five hundred and six.
(3) Fourty five lakh, seventy one thousand and five hundred and four.
(4) Twenty one lakh, nine thousand and nine hundred.
(5) Forty three lakh, seven thousand, eight hundred and fifty four
(6) Fifty lakh
(7) Sixty lakh and ten
(8) Seventy lakh and one hundred
(9) Eighty lakh and one thousand
(10) Ninety lakh and ten thousand
(11) Ninety one lakh
(12) Ninety-nine lakh, ninety-nine thousand and nine hundred and ninety-nine.
Problem set 5
1.) Write the place value of the underlined digit.
(1) 70,00,000
(2) 4,00,000
(3) 50,000
(4) 0
(5) 90,000
[Note : Place value means that number and you have to see how many digits are there in the number, that number of zero will place. Like in number 1 –
78, 95,210
Here its told to write the place value of 7.
You can see there total 6 digits after 7.
So the answer is 7000000.
Hope you understand]
2.) Write the numbers in their expanded form
(1) 50,00,000 + 6,00,000+40,000+3000+200+15
(2) 70,000+0+800+15
(3) 8,00,000+30,000+5000+900+99
(4) 8,00,000+80,000+8000+800+89
(5) 90,00,000+2,00,000+30,000+2000+900+92
3.) Write the place name and place value of each digit in the following number
(1)
3 | 5 | 7 | 0 | 5 |
Ten thousands | Thousands | Hundreds | Tens | Units |
30,000 | 5000 | 700 | 0 | 5 |
(2)
7 | 8 | 2 | 8 | 9 | 9 |
Lakhs | Ten thousands | Thousands | Hundreds | Tens | Units
|
7,00,000 | 80,000 | 200 | 800 | 90 | 9 |
(3)
8 | 2 | 7 | 4 | 5 | 0 | 8 |
Ten Lakhs | Lakhs | Ten Thousands | Thousands | Hundreds | Tens | Units |
80,00,00 | 2,00,000 | 7,000 | 4000 | 50 | 0 | 8 |
4.) The expanded form of the number is given. Write the number.
(1) 64,579
(2) 9,27,805
(3) 23,69,517
(4) 80,51,609
PROBLEM SET 6
1.) Write the proper symbol, ‘<’ or ‘>’ in the box.
(1) The place value of 5,075 is
5 | 7 | 0 | 5 |
Thousands | Hundreds | Tens | Unit |
5000 | 700 | 0 | 5 |
The place value of 15,705 is
1 | 5 | 7 | 0 | 5 |
Ten Thousands | Thousands | Hundreds | Tens | Unit |
10000 | 5000 | 700 | 0 | 5 |
As we can see from the place value,
15,705 is bigger than 5705
Rules of proper symbol indication is the arrow will always face the smaller number. If the smaller number is on the right side the arrow will point towards right side ( bigger number > smaller number)
If the smaller number is on the left side the arrow will point towards the left side ( smaller number < bigger number)
So using the proper symbol the answer will be 5,705 < 15,705.
(2) The place value of 22,774,705 is
2 | 2 | 7 | 4 | 7 | 0 | 5 |
Ten lakhs | Lakhs | Ten Thousands | Thousands | Hundreds | Tens | Units |
20,00,000 | 2,00,000 | 70,000 | 4,000 | 700 | 0 | 5 |
The place value of 12,74,705 is
1 | 2 | 7 | 4 | 7 | 0 | 5 |
Ten lakhs | Lakhs | Ten Thousands | Thousands | Hundreds | Tens | Units |
10,00,000 | 2,00,000 | 70,000 | 4000 | 700 | 0 | 5 |
As we can see from the place value,
The place value of 22,774,705 is bigger than 12,74,705.
So the arrow will face towards the smaller number 12,74,705 and as it is on right side the arrow will point to the right side.
So using proper symbol method the answer will be,
22,74,705 > 12,74,705
(3) 35,33,302 > 35,32,302
(4) 99,999 < 9,99,999
(5) 4,80,009 < 4,90,008
(6) 35,80,177 < 35,88,172
2.) Solve the problems given below.
(1) The Swayamsiddha Savings Group made 3,45,000 papads while the Swabhimani Group made 2,95,000. Which group made more papads?
The total number of papads made by Swayamsiddha Savings Group is 3,45,000.
The total number of papads made by Swabhimani Group is 2,95,000.
Using proper symbol method,
3,45,000 > 2,95,000
So from the above we can determine the Swayamsiddha Savings group made more papads.
(2) Children of the Primary School in Ahmadnagar District collected 2,00,000 seeds while those in Pune District collected 3,25,000. Which children collected more seeds ?
The total number of seeds collected by children of the primary school in Ahmadnagar district is 2,00,000
The total number of seeds collected by children of the primary school in Pune district is 3,25,000
Using the symbol method,
2,00,000 < 3,25,000
So from the above we can determine children of Pune district collected more seeds
(3) The number of people who took part in the Republic Day flaghoisting ceremony was 2,01,306 in Pandharpur taluka and 1,97,208 in Malshiras taluka. In which taluka did a larger number of people participate ?
The number of people in flaghosting ceremony in Pandharpur taluka was 2,01,306
The number of people in flaghosting ceremony in Malshiras taluka was 1,97,208
Using the symbol method,
2,01,306 > 1,97,208
So from the above we can determine in the Padharpura taluka did a did a larger number of people participate.
(4) At an exhibition, the Annapoorna Savings Group sold goods worth 5,12,345. The Nirman Group sold goods worth 4,12,900. This figure was 4,33,000 for the Srujan Group and 5,11,937 for the Savitribai Phule group.
Which group had the largest sales ?
Which group had the smallest ?
Write the sales figures in ascending order.
The Annapoorna Savings Group sold goods worth 5,12,345 rupees
The Nirman Group sold goods worth 4,12,900 rupees
The Srujan Group sold goods worth 4,33,000 rupees
The Savitribai Phule group sold goods worth 5,11,937 rupees
Using symbol method,
5,12,345 > 5,11,937 > 4,33,000 > 4,12,900
So from the above we can determine,
The Annapoorna Savings Group had the largest figure of sold goods.
The Nirman Group had the smallest figure of sold goods.
The sales figures in ascending order
4,12,900 < 4,33,000 < 5,11,937 < 5,12,345
For More Solutions, Click Below:
Part One:
- Chapter 1 Roman Numerals
- Chapter 3 Addition and Subtraction
- Chapter 4 Multiplication and Division
- Chapter 5 Fractions
- Chapter 6 Angles
- Chapter 7 Circles
Part Two: