Gay Lussac’s law Formula
It state that at constant volume the pressure of given mass of the gas is directly proportional to the temperature (absolute temperature or temperature in Kelvin).
Contents
Formula:
Volume (V) is constant
P = K.T
P/T = K
If we provide two different pressure and temperature
So equation are as follow
Problem:
10 gm of hydrogen gas pressure 0.95× 10 -5 N/ m 2at 27°C .if the volume remain constant temperature is raised to 57°C . Find the pressure of gas?
Solution:
Given data ;
P1 = 0.95× 10 -5 N/ m 2
T1 = 27° C
= 27+ 273
= 300 K
P2= ?
T1 = 57° C
= 57+ 273
= 330 K
According to Gay-Lussa’s law,