The post DAV Class 5 Math Solution Chapter 16 Triangles appeared first on Net Explanations.
]]>DAV School Books Class 5 Math Solution Chapter 16 Triangles all Question Answer. DAV Class 5 16th Chapter Triangles full Chapter explanation by expert teacher.
Page no- 185
Worksheet 1
(1) How many vertices, sides and angles does a triangle have?
Ans:- A triangle has 3 vertices, 3 sides and 3 angles.
(2) Draw a triangle. Name its vertices, sides and angles.
Ans:-
P, Q and R are the vertices of the △ PQR.
PQ, QR and PR are the sides of the △ PQR.
∠PQR or ∠Q, ∠QRP or ∠R and ∠RPQ or ∠P are the angles of the △ PQR.
(3) You are given some triangles. Name its vertices, sides and angles.
Ans:-
(4) Count and write how many triangles are there in each figure.
(a)
Ans:- 3
(b)
Ans:- 5
(c)
Ans:- 5
Page no- 188
Worksheet 2
(2) Find which of the following can be the measures of three angles of a triangle.
(a) 35°, 80°, 65°
(b) 15°, 75°, 90°
(c) 70°, 70°, 70°
(d) 45°, 59°, 81°
Ans:- (a) and (b)
(3) Can you draw a triangle with 2 right angles? Give reasons.
Ans:- No, it is impossible to draw a triangle with 2 right angles because then the sum of its three angles will be more than 180°.
(4) Can you draw a triangle with 2 obtuse angles? Give reasons.
Ans:- No, a triangle cannot be drawn with 2 obtuse angles. If we draw a triangle with 2 obtuse angles the sum of the three angles of the triangle will be more than 180° that is impossible.
(5) Find the missing angle in each of the following:
(a)
(b)
Ans:- 43°
(c)
Ans:- 100°
(6) The sum of 2 angles of a triangle is 110°. Find the measure of the third angle.
Ans:- Sum of 2 angles of a triangle = 110°
We know, Sum of three angles of a triangle = 180°
So, measure of the third angle = 180° – Sum of 2 angles
= 180° – 110°
= 70°
(7) Two angles of a triangle are 100° and 55° respectively. Find the third angle.
Ans:- Measure of the two angles = 100° and 55°
Sum of the two angles = 100° + 55°
= 155°
We know, Sum of three angles of a triangle = 180°
So, measure of the third angle = 180° – Sum of 2 angles
= 180° – 155°
= 25°
Page no- 193
Worksheet 4
(1) Identify the scalene, isosceles and equilateral triangles.
(a)
Ans:- Isosceles triangle.
(b)
Ans:- Equilateral triangle.
(c)
Ans:- Scalene triangle.
(d)
Ans:- Isosceles triangle.
(e)
Ans:- Scalene triangle.
(2) Identify the acute, obtuse and right angled triangles.
(a)
Ans:- Right angled triangle.
(b)
Ans:- Obtuse angled triangle.
(c)
Ans:- Acute angled triangle.
(3) Find the third angle of this triangle. What type of triangle is this? Why?
Ans:- We know, Sum of three angles of a triangle = 180°
The third angle of this triangle = 180° – (40° + 50°)
= 180° – 90°
= 90°
It is a right angled triangle because one of its angles is equal to 90°.
(4) Sum of 2 angles of a triangle is 90°. Find the third angle. What type of triangle is this?
Ans:- Sum of 2 angles of a triangle = 90°
We know, Sum of three angles of a triangle = 180°
Measure of the third angle = 180° – 90°
= 90°
It is a right angled triangle because one of its angles is equal to 90°.
(5) If the measure of one angle of a right angled triangle is 48°, find the other two angles.
One angle of a right angled triangle = 48°
We know that one of the three angles of a right angled triangle is 90°.
So, the third angle = 180° – (48° + 90°)
= 180° – 138°
= 42°
Ans:- The other two angles are 90° and 42°.
(6) Fill in the blanks.
(a) A triangle whose any one angle is a right angle, is called a right angled triangle.
(b) Each angle of an acute angled triangle is acute angle .
(c) Any one angle of an obtuse angled triangle is obtuse angle .
(d) A triangle whose any two sides are equal in length is called isosceles triangle.
(e) Sum of three angles of a triangle is equal to 180° .
(f) Sum of lengths of any two sides of a triangle is more than the third side.
(g) In an isosceles triangle, two any sides are equal in length.
Page no- 195
Brain Teasers
(1) A closed figure is made of three line segments. What is the figure called?
Ans:- A closed figure is made of three line segments is called a triangle.
(2) Name the vertices, sides and angles of this triangle.
Ans:- Vertices = X, Y and Z
Sides = XY, YZ and ZX
Angles = ∠XYZ, ∠YZX and ∠ZXY
(3) How many triangles are there in each?
(a)
Ans:- 5
(b)
Ans:- 6
(4) Find the missing angle. State the kind of triangle.
(a)
Ans:- Measure of the third angle = 180° – (52° + 38°)
= 180° – 90°
= 90°
It is a right angled triangle because one of its angles is equal to 90°.
(b)
Ans:- Measure of the third angle = 180° – (75° + 65°)
= 180° – 140°
= 40°
It is a acute angled triangle because all the angles of the triangle are acute.
(5) State the kind of triangle.
(a)
Ans:- This is an Isosceles triangle.
(b)
Ans:- This is an Equilateral triangle.
(6) Can you construct a triangle with angles 70°, 35°, 85°? Why?
Ans:- No, we cannot construct a triangle with angles 70°, 35°, 85° because the sum of the these angles are more than 180° whereas the sum of three angles of a triangle must be 180°.
(7) Can you construct a triangle with the line segments of length 11 cm, 7 cm and 8 cm? Give reasons.
Ans:- Yes, we can construct a triangle with the line segments of length 11 cm, 7 cm and 8 cm. As we know that the sum of any two sides of a triangle is always greater than the third side.
(8) State True or False.
(a) A triangle can have two right angles.
Ans:- False
(b) An obtuse angled triangle has one obtuse angle and two acute angles.
Ans:- True
(c) The sum of lengths of any two sides of a triangle is equal to the third side.
Ans:- False
(d) The sides of an equilateral triangle are of equal length.
Ans:- True
Also See: Chapter 7 Multiplication and Division of Decimal numbers solution
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]]>The post UP SCERT Solutions Class 6 English Chapter 14 – Netaji Chandra Bose appeared first on Net Explanations.
]]>Uttar Pradesh (UP) SCERT Class 6 English Chapter 14 Netaji Chandra Bose exercise question answer solutions is available here.
Board |
Uttar Pradesh SCERT |
Class |
6 |
Subject |
English |
Book Title |
Rainbow |
Topic |
Solution |
Chapter 14-Netaji Chandra Bose
Comprehension Questions
1.) Answer the following questions:
a.) Which Indian freedom fighter is known as Netaji?
Ans: Indian Freedom fighter Subash Chandra Bose is known as Netaji.
b.) When and where was Subash Chandra Bose born?
Ans: Shubash Chandra Bose was born on 23^{rd} January, 1897, in a Hindu family in Cuttack (Odisha).
c.) Why did Subhash Chandra Bose resign from the Indian Civil Services?
Ans: Subhash Chandra Bose resigned from the Indian Civil Services because he participated in the freedom movement.
d.) Who was the political guru of Subhash Chandra Bose?
Ans: Nationalist, Deshbandhu Chitranjan was the political guru of Subhash Chandra Bose.
e.) What does INA stand for?
Ans: INA stands for Indian National Army. It is also known as “Azad Hind Fuaz.”
f.) Write the slogans given by Subhash Chandra Bose.
Ans: The slogans given by Subhash Chandra Bose were “Delhi Chalo” , “Jai Hind” and “Give me blood and I will give you freedom”
2.) Write ‘T’ for true and ‘F’ for false statements:
a.) Subhash Chandra Bose was a great freedom fighter.
Ans: Subhash Chandra Bose was a great freedom fighter.(T)
b.) He completed his schooling in Japan.
Ans: He completed his schooling in Japan. (F)
c.) He did not resign from the Indian Civil Services.
Ans: He did not resign from the Indian Civil Services. (F)
d.) He did not want to participate in the freedom movement.
Ans: He did not want to participate in the freedom movement. (F)
e.) He formed the Indian National Congress.
Ans: He formed the Indian National Congress. (F)
Word Power
1.) Fill in the blanks with the words given in the box:
mystery, participate, influenced, freedom, brilliant
a.) Neha is a _______ student.
= Neha is a brilliant student.
b.) The _______ of the ghost was solved by the teacher.
= The mystery of the ghost was solved by the teacher.
c.) Rajni will ______ in a quiz competition at the national level.
= Rajni will participate in a quiz competition at the national level.
d.) Subhash Chandra Bose was very much _____ by Chitranjan Das.
= Subhash Chandra Bose was very much influenced by Chitranjan Das.
e.) Many great leaders sacrificed their lives for the ____ of their country.
= Many great leaders sacrificed their lives for the freedom of their country.
Language Practice
1.) Fill in the blanks with adjectives given in the books which is opposite in meaning to the underlined adjectives.
Light, soft, deep, full, present, blunt, narrow, left
a.) A shallow pool is not deep.
b.) The parcel is heavy, but the letter is …..
= The parcel is heavy, but the letter is light.
c.) Rock is hard, but wool is …..
= Rock is hard, but wool is soft.
d.) I wear my watch on the right wrist not on the …..
= I wear my watch on the right wrist not on the left.
e.) The scissor is sharp but the knife is ….
= The scissor is sharp but the knife is blunt.
f.) Ashok’s glass is empty, but Mary’s glass is …..
= Ashok’s glass is empty, but Mary’s glass is full.
g.) Sona is absent today, but Rajat is …..
= Sona is absent today, but Rajat is present.
h.) The roads in Haryana are broad, not …..
= The roads in Haryana are broad, not narrow.
Chapter 13 Little Things
The post UP SCERT Solutions Class 6 English Chapter 14 – Netaji Chandra Bose appeared first on Net Explanations.
]]>The post Chhattisgarh Class 9 Maths Solution Chapter 3 Exponent Exercise 3.2 appeared first on Net Explanations.
]]>(1) Find the value of each of the following-
(i) (16)^{1/2}
Ans:-(4^{2})^{1/2}
= 4^{1/2}
= 4
(ii) (243)^{1/5}
Ans:-(3^{5})^{1/5}
= 3^{8×1/5}
= 3^{1}
= 3
(iii) (15625)^{1/6}
Ans:-(5^{6})^{1/6}
= 5^{6 × 1/6}
= 5
(2) Simplify each of the following-
(i) 23^{1/2 }× 23^{3/2}
Ans:-23^{1/2 + 3/2}
= 23 ^{1 + 3/2}
= 23 ^{4/2}
= 23^{2}
= 529
(ii) 11^{4/3}× 11^{5/3}
Ans:-11^{4/3 + 5/3}
= 11 ^{4 + 5/3}
= 11 ^{9/3}
= 11^{3}
= 1331
(iii) 21^{7/3 }÷ 21^{1/3}
Ans:-21^{7/3 – 1/3}
= 21 ^{7 – 1/3}
= 21^{6/3}
= 21^{2}
= 441
(iv) 15^{3/2}÷ 15^{5/2}
Ans:-15^{3/2-5/2}
= 15 ^{3 – 5/2}
= 15 ^{– 2/2}
= 15^{-1}
= 1/15
(3) Find the values of-
(i) (625/81)^{4/3}÷ (625/81)^{2/3}
Ans:-(625/81)^{4/3 – 2/3}
= (625/81)^{2/3}
= (25/9)^{2× 2/3}
= (25/9)^{4/3.}
Also See:
The post Chhattisgarh Class 9 Maths Solution Chapter 3 Exponent Exercise 3.2 appeared first on Net Explanations.
]]>The post Chhattisgarh Class 9 Maths Solution Chapter 3 Exponent Exercise 3.1 appeared first on Net Explanations.
]]>(1) Find the values of –
(i) (1/2)^{-5}
Ans:-1^{-5}/2^{-5} = 1/1^{5}/1/2^{5} = 2^{5}/1 = 32
(ii) 1/3^{-4}
Ans:-1/1/3^{4} = 3^{4} = 81
(iii) 6^{7}/2^{3}× 3^{7}
Ans:-2^{7}× 3^{7}/2^{3}× 3^{7}
= 2^{7– 3 }× 3^{7 – 7}
= 2^{4}× 3
= 16 × 1
= 16
(2) Simplify each of the following-
(i) (-4)^{3}× (-2)^{-3}
Ans:-[-(2^{2})]^{3}× (-2)^{-3}
= -2 ^{2 × 3}× (-2)^{-3}
= 2 ^{6 + (-3)}
= 2^{3 }
= 8
(ii) (-3)^{4}× (5/3)^{4}
Ans:-(-3)^{4}× 1/3^{4}× 5^{4}
= -3^{4-4 }× 5^{4}
= (-3)^{0}× 5^{4}
= 5^{4}× 1
= 625
(iii) (-5)^{3}÷ (5)^{-7}
Ans:--5^{3}/5^{-7}
= (-5)^{3 }– (-7)
= (-5)^{10}
= – 9765625
(3) Simplify-
(i) 16 × t^{-3}/4^{-3}× 8 × t^{-6} (t ≠ 0)
Ans:-2^{4}× t^{-3-(-6)}/2^{-3 × 2}× 2^{3}
= 2^{4}× t^{3}/2^{-6}× 2^{3}
= 2^{4}× t^{3}/2^{-6 + 3}
= 2^{4}× t^{3}/2^{-3}
= 2^{4– (-3)}
=2^{4} – ^{(-3)}× t^{3}
= 2^{7}× t^{3}
= 128 t^{3}
(ii) {(1/3)^{-1} – (1/4)^{-1}}^{-1}
Ans:-{1/3^{-1} – 1/4^{-1}}^{-1}
= {3 – 4}^{-1}
= -1^{-1}
= -1
(4) Prove-
(i) (x^{a}/x^{b})^{a+b}× (x^{b}/xc)^{b+c}×(x^{c}/x^{a})^{c+a} = 1
Ans:-
LHS.
= (x^{a}/x^{b})^{a+b}× (x^{b}/x^{c})^{b+c}× (x^{c}/x^{a})^{c+a}
= (x^{a-b})^{a + b}× (x^{b – c})^{b + c}× (x) ^{(c – a) (c + a)}
= x ^{a2 – b2}×x^{b2 – c2 }×x^{c2 – a2}
= x ^{a2-b2 + b2-c2 + c2 – a2}
= x^{0}
= 1 = RHS
(5) Write the following numbers in the standard form-
(i) 0.00000000000852
Ans:-852/10^{110}
= 852 × 10 ^{– 14}
= 8.52 × 10^{2}× 10 ^{– 14}
= 8.52 × 10^{-12}
(ii) 8020000000000000
Ans:-802 × 10^{13}
= 8.02 × 10^{2}× 10^{13}
= 8.02 × 10^{15}
(iii) 41960000000
Ans:-4196 × 10^{7}
= 4.196 × 10^{3 }× 10^{7}
= 4.196 × 10^{10}
(6) Express the following numbers in the decimal form-
(i) 5.02 × 10^{-6}
Ans:-5.02/10^{6}
= 502 × 10^{-2}/10^{6}
= 502/10^{6 + 2}
= 502/10^{8}
= 0.00000502
(ii) 7 × 10^{-8}
Ans:-7/10^{8}
= 0.00000007
(iii) 1.0000 × 10^{9}
Ans:-100001 × 10^{-5}× 10^{4}
= 100001 × 10^{4}
= 1000010000.
(7) Write numbers in the following statements in standard form-
(i) Size of red blood cells is 0.000007 m.
Ans:-Size of Red blood cell is 0.000007 m.
= 7 × 10-6 m.
(ii) The diameter of the Earth is 12756000 m.
Ans:-The diameter of earth is 12756000 m.
= 1.2756 × 10^{7}m.
(iii) Thickness of a paper is 0.08 m.
Ans:-Thickness of a Paper is 0.08 m.
= 8 × 10^{-2} m.
Also Solved
The post Chhattisgarh Class 9 Maths Solution Chapter 3 Exponent Exercise 3.1 appeared first on Net Explanations.
]]>The post UP SCERT Solutions Class 6 English Chapter 13 – Little Things appeared first on Net Explanations.
]]>Uttar Pradesh (UP) SCERT Class 6 English Chapter 13 Little Things exercise question answer solutions is available here.
Board |
Uttar Pradesh SCERT |
Class |
6 |
Subject |
English |
Book Title |
Rainbow |
Topic |
Solution |
Chapter 13- Little Things
Comprehension Questions
1.) Answer the following questions:
a.) What makes the ocean mighty?
Ans: Little drops of water make the ocean mighty.
b.) Where do our little errors lead the soul?
Ans: Our little errors lead the soul away from the path of virtue and far in the right way of life.
c.) Which are the things that make the earth more like heaven?
Ans: Our kindness, love and effort make the earth more like heaven.
Word Power
1.) What do they make:
a.) Little drops of water – __
= little drops of water – the mighty ocean.
b.) Little grains of sand – __
= Little grains of sand pleasant land.
c.) Little moments – _
= Little moments – mighty ages.
d.) Little deeds of kindness – _
= Little deeds of kindness – earth happy.
2.) Write one more rhyming words:
Sand land hand band
Make take fake cake lake shake
Grain train drain brain
Age page mage sage cage
Drop crop prop
Extra Questions:
1.) What makes the mighty ages of eternity?
Ans: Small moments and humble thought make the mighty ages of eternity.
2.) What does lead the soul away from the path of virtue?
Ans: The little errors lead the soul away from the path of virtue and from the correct path.
Chapter 12 Safety Saves
The post UP SCERT Solutions Class 6 English Chapter 13 – Little Things appeared first on Net Explanations.
]]>The post DAV Class 6 English Literature Book Solution Chapter 7 Bharat Desh appeared first on Net Explanations.
]]>DAV School Class 6 English Literature Book Solution Chapter 7 Bharat Desh all Question Answer. DAV Class 6 7th Chapter Bharat Desh full Chapter explanation by expert teacher.
Understanding the story
A) Now read the gist of the poem given below. Fill in the blanks with appropriate words or phrases.
Though the poem Bharat Desh, the speaker wants us to shake off our fears and poverty and set up schools for the students. He wants us to produce tools, weapons and paper. He advised us not to be lazy or weary and try to be generous. He wants his countrymen to know more about scriptures , sciences and oceans. Following all this, our country shall rise high and prosper.
B) On the basis of your understanding of the poem, match the following phrases appropriately (as done in the example):
A | B |
Shake off | Fears and poverty |
Stroll on | Snow clad silvery heights |
Sail across | The high seas |
Set up | Schools, all sacred temples |
Thump | Our shoulders |
Make | Tools and weapons |
Produce | Paper |
Open | Factories and schools |
Never be | Lazy and weary |
Ever be | Generous |
Speak | The truth |
Learn | Scriptures and sciences |
Explore | Heavens and oceans |
Unravel | Mysteries of moon |
C)
D) Given below are examples of metaphor. Complete these by feeling in the blanks with appropriate words from the box given below.
1) The baby has a soft skin. Her rabbit skin fascinated me.
2) Ravi is the bravest soldier in the army. He is a lion amongst others.
3) Shiv is a very swift child. He is the cheetah of his class.
4) Chintu imitates his elder brother. His brother gets irritated by this little monkey.
(II) HOTS
What should be our priority – our personal growth or our motherland’s growth.
Answer – Both personal growth and motherland’s growth is equally important. Balancing both is very important, but it shouldn’t be a competition. While personal growth is important for an individual, growth of our motherland is our moral duty as an responsible citizen.
According to me giving priority to personal growth is directly connected to our motherland’s growth too. If one can become a capable, informed, empathetic and successful individual, he/she can contribute towards the well-being of the nation on a larger scale.
(III) Life skills
A) some children of your class often speak about going abroad for the studies and their plans to settle there. You strongly feel that one should stay in one’s own country. How you help them see your point of view?
Answer – One should stay in one’s own country because of reasons such as,
B) Why it is important to learn scriptures as well as sciences? Discuss with your partner.
Answer – It’s important to learn both scriptures and sciences. It is because both of themteaches us different things in life. On one side scriptures help us how to live a life of truth,how to ne kind, how to make good choices, and live a peaceful and healthy life. On the other hand science helps us understand how the world works, like how plants grow or how the weather changes. Learning both helps us grow as good people who know how to take care of the world and each other.
(IV) Values
The poem Bharat Desh highlights certain important values, which the citizens of a country need to embed in themselves to make their country progress. Can you shortlist them?
Answer –
The important values citizens of a country need to embed in themselves to make their country progress are,
(V) Writing skills
Write a short paragraph : ‘I am proud to be an Indian.’
I am proud to be an Indian. Our a nation is rich in history, culture, and diversity. The greatest characteristic of India is the unity in diversity. India has different religions, different languages and its vibrant traditions. Though we have so many cultures, we all are united and stay peacefully together. From ancient civilizations India was an leading nation in arts, science, medicine, education. It’s my honor and I am blessed to being part of this incredible nation.
Also See: Attila chapter all question answer
The post DAV Class 6 English Literature Book Solution Chapter 7 Bharat Desh appeared first on Net Explanations.
]]>The post DAV Class 6 English Literature Book Solution Chapter 10 Attila appeared first on Net Explanations.
]]>DAV School Class 6 English Literature Book Solution Chapter 10 Attila all Question Answer. DAV Class 6 10th Chapter Attila full Chapter explanation by expert teacher.
Understanding the story.
A) Answer the following questions briefly
1) Why did the family but Attila?
Answer – To safeguard the house from possible housebreaking and theft.
2) What was Attila’s attitude towards strangers?
Answer – Attila’sshowed a love of humanity and a gentle behaviour towards strangers.
3) What was Attila’s reaction when he saw Ranga stealing the valuables? How far was it in accordance with Ranga’s expectation.
Answer –When Attila’s saw Ranga saw stealing the valuables, he licked Ranga’s hand and rolled his eyes, he didn’t even bark.
It was very far in accordance with Ranga’s expectations.
4) Why was Ranga fed up with Attila?
Answer – Ranga was fed up with Attila because Attila won’t leave him no matter how much he tells it.
5) How did the family members react to Attila’s disappearance?
Answer – Everyone reacted differently to Attila’s disappearance, mother thought it was a shame and father thought it’s a relief and the thief should keep all the jewels as a reward for taking the dog.
6) Why did Attila run after Ranga? What did others conclude from his chase?
Answer –Attila ran after Ranga because he thought Rangagonna leave him.
Other’s thought he wanted to stop Ranga from running away.
B) Fill in the chart below highlighting the difference between what was expected of Attila and what he actually did.
Expectations of the family |
Attila’s behavior |
Strong and aggressive |
Gentle and friendly |
Catch the flower thief |
Won’t do anything about it |
Scare away strangers |
Showed a love of humanity and a gentle behavior |
Bark at the thief |
Lick the hands of thief and do nothing |
(II) HOTS
A) Is Attila really a hero? Give Reasons for your answer.
Answer – Yes, if you see this without knowing the whole story Attila really is a hero. He went with the thief and for that reason only the eldest son could recognize and capture the thief.
B) All said and done, Attila was a bad watchdog. Do you agree?
Answer – Yes, I agree that Attila was a bad watchdog.
(III) Life skills
As the youngest son, who always favored Attila. What would you do to help the family come out of the shock?
Answer – I would look out for Attila everywhere and wherever Attila would be present there is a chance that the thief might be present too as the thief seemed to take Attila with him. And after locating Attila I would figure out who is the thief and catch him.
(IV) Values
‘We should judge people by what they actually are and not by what they help or achieve.’ Discuss with reference to Attila.
Answer – If we take reference of Attila, he is a nice dog. He has a love for humanity and shows gentle behavior. But because he is being brought for guarding most of the people in family doesn’t like him. But if they liked him as he is, they would be happy to have him.
(V) Writing skills
A) Imagine yourself to be a newspaper reporter who witnessed Attila blocking the way of Ranga and helping the police catch the thief. Write a newspaper report describing the brave act of Attila.
BRAVE DOG ‘ATTILA’ CATCHES THIEF
Yesterday a bravedog ‘Attila’ helps police catch a thief. A thief ‘Ranga’ was causing lots of break ins and theft. Recently he stole lots of Jewellery from a house. But when a boy ran to catch he started running but Attila ran behind him and he fell down.
B) Imagine yourself to be Attila. Write a letter to one of your friends showing your displeasure over your friendRanga’s imprisonment.
Dear ______ ,
Hope you are well. I am writing this letter to inform you that yesterday police caught my friend Ranga. I met him someday before at night in my previous home. He was taking somethings late at night but when I met him I instantly liked him. Then oneday he started running and I feared he would leave me. So I ran towards him and he fall down stumbled upon me. Then the eldest son of previous home started beating him and police came and caught him. I am so sad, I hope they let him out.
Your obediently,
Attila
Also See: Next chapter The Case of Copied Question Papers full solution
The post DAV Class 6 English Literature Book Solution Chapter 10 Attila appeared first on Net Explanations.
]]>The post PSEB Class 6 Agriculture Chapter 5 Fertilizers Solution appeared first on Net Explanations.
]]>PSEB Punjab Board Class 6 Agriculture Textbook Solution Chapter 5 Fertilizers Exercise Questions and Answers is available here.
A.) Answer in 1 to 2 words
1.) How many nutrients are required for growth and development of plants?
Answer –Seventeen types.
2.) Name the two types of fertilizers.
Answer –Organic fertilizers and inorganic chemical fertilizers.
3.) Name the crops which can fix atmospheric nitrogen into their roots.
Answer –Jantar/dhaincha, sunnhemp, cowpea etc.
4.) What is the change in soil with excessive use of nitrogenous fertilizers?
Answer –Increased acidic contents of soil.
5.) What percent of nitrogen is present in atmosphere in the form of gas?
Answer –78%.
6.) What percent of phosphorus is present in 100 kg of DAP?
Answer –46%.
7.) What is the main source of phosphorus content?
Answer –Farmyard Manure.
8.) What are the nutrients present in 100 kg FYM?
Answer –Urea and phosphorus
9.) Potassium is generally applied in which crop in Punjab?
Answer –Potato
10.) What percent of nitrogen is present in 100 kg urea?
Answer –46%
B.) Answer in 1 to 2 sentences:
1.) What are manures?
Answer –Manure is a natural substance which is made from decomposition of cattle dung, human waste and plant waste.
2.) What do you understand by green manuring?
Answer –Green mannuring is a process in which crops such as jantar/dhaincha, sunnhemp, cowpea etc. are ploughed and incorporated in the soil while they are standing green or soon after they flower.
3.) How do organic fertilizers sustain the soil fertility for a longer time?
Answer –Organic fertilizers contains humus, which helps the soil to sustain fertility for a longer time.
4.) Which fertilizers are used more commonly under Punjab conditions?
Answer –Urea, Diammonium Phosphate, Muriate of Potash etc. are used more commonly under Punjab conditions.
5.) How is Urea fertilizer prepared?
Answer –Urea fertilizer is prepared from atmospheric nitrogen. 46% nitrogen is present in Urea fertilizer.
6.) Which mineral is used to obtain Phosphorous?
Answer –Rock phosphate minerals is used to obtain Phosphorus.
7.) How Farmyard Manure is beneficial to soil?
Answer – Farmyard Manure contains humus, which helps to sustain the soil fertility.
8.) What are the symptoms of Nitrogen deficiency in crops?
Answer –The symptoms of Nitrogen deficiency in crops are yellow coloration of leaves in below at first then moving upwards to yellow coloration of whole plants.
9.) How are chemical fertilizers useful for plants?
Answer –Chemical fertilizers contains more amount of useful specific nutrients than manures. If the soil is deficit of particular nutrient, then chemical fertilizer containing particular nutrient can be used.
10.) How is vermicompost prepared?
Answer –Vermicompost is prepared by mixing plant residues and dung with the help of earthworms.
C.) Answer in 5 to 6 sentences:
1.) What do you understand by fertilizers? Explain.
Answer –Fertilizers are outside substances which provide nutrient requirements of crops to provide high yield. Fertilizers contains many nutrients. Fertilizers are two types. These are Organic and Inorganic chemical fertilizers. Some of the fertilizers are used before sowing the crops and some of them are used after sowing.
2.) Write a short note on chemical fertilizers.
Answer – Chemical fertilizers are a type of fertilizer. They are made by humans in factories. Chemical fertilizers contains nitrogen, Phosphorus and potassium. They are inorganic in nature and contains more amount of nutrients than manures. Chemical fertilizers may contain specific nutrients as per required by the crops. They do not contain humus.
3.) Write a short note on harmful effect of chemical fertilizers on soil.
Answer – Excessive use of chemical fertilizers has very bad effect on our environment. Excessive use of nitrogenous fertilizers may result in increase in the acidic content in the soil. This fertilizers are water soluble so we can easily contaminate the water reservoirs such as ponds lakes rivers canals etc. Which may result in increased growth of unwanted plantssuch as algae and water hyacinth.
4.) What measures should be taken to maintain the fertility of soils?
Answer – To maintain soil fertility farmers should balance the use of organics and inorganic fertilizers. The organic fertilizers contain less nutrients and more humus, which is good for maintaining soil fertility and inorganic fertilizers contains more nutrients and less humus. So balance is required to get more yield and sustain soil fertility. Excessive use of chemical fertilizers can also cause harm to the soil. So reducing use of chemical fertilizers is necessary to maintain soil fertility.
5.) What is the importance of farmyard manure?
Answer –Farmyad manure is one of the most important and widely used manure. They are made from cow dung, human waste and plant waste. These are not harmful for nature and contains humus. Humus helps to sustain soil fertility .
Also See: Previous chapter 4 all question answer
The post PSEB Class 6 Agriculture Chapter 5 Fertilizers Solution appeared first on Net Explanations.
]]>The post Chhattisgarh Class 4 Math Addition and Subtraction Solution appeared first on Net Explanations.
]]>CG Board Class 4 Math Solution for Lesson 2 Addition and Subtraction all Questions Answer.
Write numbers in the boxes as shown.
17 add 5 = 22 subtract 8 = 14 add 3=17
25 subtract 8= 17 add 12= 29 subtract 4= 25
42 subtract 12= 30 add 18= 48 subtract 6= 42
35 subtract 8= 27 add 6= 33 add 12= 45 subtract 10= 35
180- 40= 140 + 60= 200- 70=130+50=180
40+4= 44-28=16+22=38 +17= 55-20= 35+18= 53- 13= 40
172-132= 40- 35=5 +42= 47+48= 95-38= 57+15= 72+ 100= 172
Understand the pattern and proceed
1.) 1+2+3=6
2+3+4= 9
3+4+5=12
= 4+5+6= 15
5+6+7= 18
6+7+8= 21
2.) 1+2+3 = 6
4+5+6 = 15
7+8+9 = 24
=10+11+12= 33
13+14+15= 42
16+17+18= 51
3.) 2+4+6 = 12
8+10+12 = 30
= 14+ 16+ 18=48
20+22+24= 66
26+28+30= 84
4.) 1+3+5 = 9
7+9+ 11 = 27
13+15+17= 45
19+21+23= 63
5.) Ans:
6.) Ans:
In the same way you also make two patterns :-
Add and subtract in the following boxes
+ | 731 | 605 | 615 |
210 | 941 | 815 | 825 |
318 | 1049 | 923 | 933 |
605 | 1336 | 1210 | 1220 |
– | 881 | 7005 | 6382 |
613 | 268 | 6392 | 5769 |
780 | 101 | 6225 | 5602 |
103 | 778 | 6902 | 6279 |
7 | 8 | 5 | 0 | |
-3 | 0 | +2 | 5 | |
4 | 8 | > | 2 | 5 |
5 | 0 | 1 | 4 | |
-1 | 2 | +2 | 3 | |
3 | 8 | > | 3 | 7 |
9 | 9 | 4 | 4 | |
-2 | 1 | +1 | 5 | |
7 | 8 | > | 5 | 9 |
6 | 7 | 4 | 9 | |
-4 | 0 | -4 | 4 | |
2 | 7 | < | 9 | 3 |
See the table and give the answers:
221 | 222 | 223 | 224 | 225 | 226 | 227 | 228 | 229 | 230 |
231 | 232 | 233 | 234 | 235 | 236 | 237 | 238 | 239 | 240 |
241 | 242 | 243 | 244 | 245 | 246 | 247 | 248 | 249 | 250 |
251 | 252 | 253 | 254 | 255 | 256 | 257 | 258 | 259 | 260 |
How much more is 231 than 221-
= 10
How much more is 241 than 231 –
= 10
How much more is 251 than 241 –
= 10
How much more is 243 than 242-
=1
How much more is 244 than 243 –
= 1
How much more is 245 than 244
= 1
The question given below are solved by Rahul and Riya. Tell who has solved the questions correctly. Write his/ her name in the box.
712+18, 216+17, 762+176, 800-191
How much price?
The price of a buffalo is Rs 5000/- . The cost of a cow is Rs 3000 and the cost of a goat is Rs 1000. See the picture and say:
1.) Add the cost of all the animals in each column and write the answers in the blank box.
First column animal’s price –
Buffalo- 5000
Goat- 1000
Goat- + 1000
Total 7000
First column animals price total: 7000/-
Second column animal’s price –
Cow- 3000
Buffalo- 5000
Cow- + 3000
Total 11000
Second column animals price total: 11000/-
Third column animal’s price –
Goat- 1000
Buffalo- 5000
Cow- +3000
Total 9000
Third column animals price total: 9000/-
2.) Write the total cost of the cows in the given box.
= are 3 cows in the given box.
The total cost of the cows are (3000+3000+3000) = 9000/-
3.) Tell the total cost of two cows and two goats.
= two cows cost- 6000/-
Two goat cost- 2000/-
The total cost of two cows and two goats: (6000+2000)= 8000/-
4.) Tell the total cost of 1 cow and 3 goats.
1 cow cost- 3000/-
3 goats cost- 3000/-
total cost = 6000/-
5.) How many goats can be purchased in the price of one buffalo?
1 buffalo price- 5000/-
1 goat price- 1000/-
So, 5 goats can be purchased in the price of one buffalo.
6.) Shalu purchased one cow, one buffalo and one goat. After that she had sufficient money to purchase a goat. Tell how much money she had.
Ans: She had 10000/- money.
Write the answers in expanded form :
1.) 2721 and 2620
2721= | 2000+ | 700+ | 20+ | 1 |
2620= | 2000+ | 600+ | 20+ | 0 |
4000+ | 1300+ | 40+ | 1 |
Or, 4 Th + 13 H+ 40 T+ 1 Ones
Or, 4 Th + 13 H+ 4 T+ 1 Ones
Or, 5 Th + 3 H+ 4 T+ 1 Ones
= The sum is 5341
2.) 3510 and 2410
3510= | 3000+ | 500+ | 10+ | 0 |
2410= | 2000+ | 400+ | 10+ | 0 |
5000+ | 900+ | 20+ | 0 |
5 Th + 9 H+ 2 Tens + 0 ones
The sum is 5920
3.) 4618 and 3206
4618= | 4000+ | 600+ | 10+ | 8 |
3206= | 3000+ | 200+ | 0+ | 6 |
7000+ | 800+ | 10+ | 14 |
Or, 7 Th+ 8 H+ 1 Tens+ 14 Ones
Or, 7 Th+ 8 H+ 2 Tens+ 4 Ones
The sum is 7824
4.) 7390 and 2000
7390= | 7000+ | 300+ | 90+ | 0 |
2000= | 2000+ | 0+ | 0+ | 0 |
9000+ | 300+ | 90+ | 0 |
9 Th+ 3 H+ 9 T+ 0 Ones
The sum is 9390.
5.) 5881 and 2830
5881 = | 5000+ | 800+ | 80+ | 1 |
2830= | 2000+ | 800+ | 30+ | 0 |
7000+ | 1600+ | 110+ | 1 |
Or, 7 Th+ 16 H+ 11 T+ 1 Ones
Or, 7 Th+ 17 H+ 1 T+ 1 Ones
Or, 8 Th+ 7 H+ 1 T+ 1 Ones
The sum is 8711
6.) 8215 and 1037
8215= | 8000+ | 200+ | 10+ | 5 |
1037= | 1000+ | 0+ | 30+ | 7 |
9000+ | 200+ | 40+ | 12 |
Or, 9 Th+ 2 H+ 4 T + 12 ones
Or, 9 Th+ 2 H+ 5 T+ 2 ones
The sum is 9252
Subtract in expanded form :
1.) 2100 from 6301
6301= | 6000+ | 300+ | 0+ | 1 |
2100= | 2000+ | 100+ | 0+ | 0 |
4000+ | 200+ | 0+ | 1 |
4 Th+ 2 H+ 0 T+ 0 Ones
= 4200
2.) 3000 from 5810
5810= | 5000+ | 800+ | 10+ | 0 |
3000= | 3000+ | 0+ | 0+ | 0 |
2000+ | 800+ | 10+ | 0+ |
2 Th+ 8 H+ 1 T+ 0 Ones
= 2810
3.) 4210 from 5380
5380= | 5000+ | 300+ | 80+ | 0 |
4210= | 4000+ | 200+ | 10+ | 0 |
1000+ | 100+ | 70+ | 0 |
1 Th+ 1 H+ 7 T+ 0 Ones
= 1170
4.) 4000 from 5000
5000= | 5000+ | 0+ | 0+ | 0 |
4000= | 4000+ | 0+ | 0+ | 0 |
1000+ | 0+ | 0+ | 0 |
Ans: 1 Thousands
5.) 6000 from 6000
6000= | 6000+ | 0+ | 0+ | 0 |
6000= | 6000+ | 0+ | 0+ | 0 |
0 | 0 | 0 | 0 |
Ans: 0
6.) 1037 from 8215
8215= | 8000+ | 200+ | 10+ | 5 |
1037= | 1000+ | 0+ | 30+ | 7 |
7000+ | 100+ | 70+ | 8 |
7 Th+ 1 H+ 7 T+ 8 Ones
= 7178
Addition of numbers having 3 digits:
Solve these :
1.)
1 | 2 | 7 | |
+ | 2 | 1 | 0 |
+ | 2 | 4 | 2 |
5 | 7 | 9 |
2.)
1 | 2 | 4 | |
+ | 2 | 6 | 7 |
+ | 7 | 1 | 3 |
1 | 1 | 0 | 4 |
3.)
1 | 4 | 5 | |
+ | 2 | 4 | 6 |
+ | 1 | 3 | 2 |
5 | 2 | 3 |
4.)
1 | 1 | 5 | |
+ | 1 | 0 | 6 |
+ | 7 | 0 | 3 |
9 | 2 | 4 |
Number 1 to 100 are written in these boxes.
In number 13, the sum of both the digits 1+3 = 4. In the same way, in number 57 the sum of both the digits is 5+7 = 12 and 1+2 = 3.
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 |
21 | 22 | 23 | 24 | 25 | 26 | 27 | 28 | 29 | 30 |
31 | 32 | 33 | 34 | 35 | 36 | 37 | 38 | 39 | 40 |
41 | 42 | 43 | 44 | 45 | 46 | 47 | 48 | 49 | 50 |
51 | 52 | 53 | 54 | 55 | 56 | 57 | 58 | 59 | 60 |
61 | 62 | 63 | 64 | 65 | 66 | 67 | 68 | 69 | 70 |
71 | 72 | 73 | 74 | 75 | 76 | 77 | 78 | 79 | 80 |
81 | 82 | 83 | 84 | 85 | 86 | 87 | 88 | 89 | 90 |
91 | 92 | 93 | 94 | 95 | 96 | 97 | 98 | 99 | 100 |
Now in these boxes write the sum of the digits & complete the square.
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 1 | 2 |
3 | 4 | 5 | 6 | 7 | 8 | 9 | 1 | 2 | 3 |
4 | 5 | 6 | 7 | 8 | 9 | 1 | 2 | 3 | 4 |
5 | 6 | 7 | 8 | 9 | 1 | 2 | 3 | 4 | 5 |
6 | 7 | 8 | 9 | 1 | 2 | 3 | 4 | 5 | 6 |
7 | 8 | 9 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
8 | 9 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
9 | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 |
1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 1 |
Write three numbers, the sum of which is 125 –
27+ 50+ 48= 125
50+ 50+ 25= 125
25+ 25+ 75= 125
30+ 30+ 65= 125
45+ 45+ 35= 125
Solve these questions –
1.) There are 438 students in Patel Para School. Out of which 198 are girls. What is the number of boys in the school?
Total students = 438
girl students =198
The number of boy students is (438-198)
4 | 3 | 8 | |
– | 1 | 9 | 8 |
2 | 4 | 0 |
= 240
Ans: The number of boys in the school is 240.
2.) In a garden, there are 245 mango trees, 368 guava trees and 154 papaya trees. What is the total number of trees in the garden ?
Mango trees+ | 2 | 4 | 5 |
Guava trees + | 3 | 6 | 8 |
Papaya trees + | 1 | 5 | 4 |
Total number of trees | 7 | 6 | 7 |
Ans: The total number of trees in the garden is 767.
3.) In a school there are 435 Hindi books, 412 Maths books and 138 English books. Write the total number of books.
Hindi Books+ | 4 | 3 | 5 |
Maths Books + | 4 | 1 | 2 |
English Books + | 1 | 3 | 8 |
Total Books | 9 | 8 | 5 |
Ans: The total number of books is 985.
4.) One boy purchased a copy containing 360 pages. He wrote on 272 pages in a few days. How many pages are blank ?
Total Pages | 3 | 6 | 0 |
Used page – | 2 | 7 | 2 |
Blank pages | 0 | 9 | 8 |
Ans: 98 pages are blank.
5.) Hindi, Mathematics and English books contain 368, 370 and 205 pages respectively. Find the total number of pages.
Pages of Hindi Book+ | 3 | 6 | 8 |
Pages of Mathematics Book+ | 3 | 7 | 0 |
Pages of English Book + | 2 | 0 | 5 |
Total pages | 9 | 4 | 3 |
Ans: The total number of pages is 943.
6.) In an election of the gram panchayat first candidate got 638 votes, the second candidate got 758 votes and was elected. Say, the candidate was defeated by how many votes?
Second candidate got | 7 | 5 | 8 |
First candidate got – | 6 | 3 | 8 |
1 | 2 | 0 |
Ans: The candidate was defeated by 120 votes.
7.) 352 and 256 guavas were plucked from two different gardens. Tell, How many more guavas were plucked from first garden?
3 | 5 | 2 | |
– | 2 | 5 | 6 |
0 | 9 | 6 |
Ans: 96 guavas were plucked from first garden.
Solve these
1.)
T | H | T | O | |
4 | 3 | 8 | 5 | |
+ | 2 | 8 | 7 | 6 |
7 | 2 | 6 | 1 |
2.)
T | H | T | O | |
5 | 7 | 3 | 8 | |
+ | 2 | 5 | 7 | 5 |
8 | 3 | 1 | 3 |
3.)
T | H | T | O | |
3 | 4 | 7 | 5 | |
+ | 3 | 6 | 8 | 7 |
7 | 1 | 6 | 2 |
4.)
T | H | T | O | |
6 | 3 | 4 | 6 | |
+ | 2 | 8 | 2 | |
6 | 6 | 2 | 8 |
5.)
T | H | T | O | |
3 | 4 | 3 | 6 | |
+ | 2 | 0 | 8 | |
3 | 6 | 4 | 4 |
6.)
T | H | T | O | |
5 | 7 | 8 | 5 | |
+ | 3 | 5 | 1 | 2 |
9 | 2 | 9 | 7 |
7.) 7213 + 2587
T | H | T | O | |
7 | 2 | 1 | 3 | |
+ | 2 | 5 | 8 | 7 |
9 | 8 | 0 | 0 |
8.) 1111 + 1199
T | H | T | O | |
1 | 1 | 1 | 1 | |
+ | 1 | 1 | 9 | 9 |
2 | 3 | 1 | 0 |
9.) 5789 + 3122
T | H | T | O | |
5 | 7 | 8 | 9 | |
+ | 3 | 1 | 2 | 2 |
8 | 9 | 1 | 1 |
10.) 4747 + 4363
T | H | T | O | |
4 | 7 | 4 | 7 | |
+ | 4 | 3 | 6 | 3 |
9 | 1 | 1 | 0 |
11.) 689 + 4678
T | H | T | O | |
4 | 6 | 7 | 8 | |
+ | 6 | 8 | 9 | |
5 | 3 | 6 | 7 |
12.) 7172 + 938
T | H | T | O | |
7 | 1 | 7 | 2 | |
+ | 9 | 3 | 8 | |
8 | 1 | 1 | 0 |
The subtraction of 4 digit number:-
Solve these
1.)
T | H | T | O | |
5 | 0 | 7 | 8 | |
– | 2 | 7 | 8 | 4 |
2 | 2 | 9 | 4 |
2.)
T | H | T | O | |
7 | 9 | 8 | 1 | |
– | 2 | 5 | 0 | 3 |
5 | 4 | 7 | 8 |
3.)
T | H | T | O | |
5 | 6 | 7 | 2 | |
– | 3 | 2 | 4 | 0 |
2 | 4 | 3 | 2 |
4.)
T | H | T | O | |
3 | 5 | 6 | 3 | |
– | 2 | 7 | 0 | 6 |
0 | 8 | 5 | 7 |
5.)
T | H | T | O | |
6 | 2 | 3 | 0 | |
– | 2 | 4 | 5 | 1 |
3 | 7 | 7 | 9 |
6.)
T | H | T | O | |
2 | 5 | 0 | 8 | |
– | 1 | 3 | 9 | 2 |
1 | 1 | 1 | 6 |
7.) 5643 – 2154
T | H | T | O | |
5 | 6 | 4 | 3 | |
– | 2 | 1 | 5 | 4 |
3 | 4 | 8 | 9 |
8.) 9634 – 5071
T | H | T | O | |
9 | 6 | 3 | 4 | |
– | 5 | 0 | 7 | 1 |
4 | 5 | 6 | 3 |
9.) 5000 – 2550
T | H | T | O | |
5 | 0 | 0 | 0 | |
– | 2 | 5 | 5 | 0 |
2 | 4 | 5 | 0 |
10.) 7111 – 5222
T | H | T | O | |
7 | 1 | 1 | 1 | |
– | 5 | 2 | 2 | 2 |
1 | 8 | 8 | 9 |
11.) 4444 – 2165
T | H | T | O | |
4 | 4 | 4 | 4 | |
– | 2 | 1 | 6 | 5 |
2 | 2 | 7 | 9 |
12.) 8100 – 7899
T | H | T | O | |
8 | 1 | 0 | 0 | |
– | 7 | 8 | 9 | 9 |
0 | 2 | 0 | 1 |
The population of 3 villages are in written below :
Ladies | Men | Boys | Girls | |
Bhanupratappur | 4134 | 3975 | 1152 | 1152 |
Basna | 3412 | 3116 | 1017 | 1075 |
Abhanpur | 3532 | 3580 | 875 | 915 |
See this table and answer the questions :-
1.) How many people live in Bhanupratappur ?
TH | H | T | O | |
4 | 1 | 3 | 4 | |
+ | 3 | 9 | 7 | 5 |
+ | 1 | 1 | 5 | 2 |
+ | 9 | 8 | 7 | |
1 | 0 | 2 | 4 | 8 |
Ans: 10248 people live in Bhanupratappur.
2.) In Basna how many men are less than women?
T | H | T | O | |
3 | 4 | 1 | 2 | |
– | 3 | 1 | 1 | 6 |
2 | 9 | 6 |
Ans: 296 men are less than woman.
3.) How many boys live in Bhanupratappurand Basna?
TH | H | T | O | |
+ | 1 | 1 | 5 | 2 |
+ | 1 | 0 | 1 | 7 |
2 | 1 | 6 | 9 |
Ans: 2169 boys live in Bhanupratappur and Basna.
4.) What is the total number of boys and girls in Abhanpur?
TH | H | T | O | |
+ | 8 | 7 | 5 | |
+ | 9 | 1 | 5 | |
1 | 7 | 9 | 0 |
Ans: The total number of boys and girls in Abhanpur is 1790.
See the picture and tell :
Edible things | Wheat | Rice | Maida | Sugar | Salt | Rawa | Peas | Paddy |
In a Bag | 75 kg | 50 kg | 50 kg | 50 kg | 40 kg | 40 kg | 75 kg | 75 kg |
= 120 kg.
= 320 kg.
= Rawa’s sacks weight= 120 kg and maida’s weight= 150 kg
= (150-120)=30 kg
= 30 kg.
=40 kg(salt, Rawa), 50 kg(Rice, Maida, Sugar), 75 kg (Wheat, Peas, Paddy)
= 150 kg.
= The maximum weight = paddy (450 kg)
Minimum weight= Sugar (100 kg)
= 31.
See the picture and say who has spent how much money to purchase things at the following price :
Harpal purchased cycle and T.V.
= (1860+5200)
=7060
Dinesh purchased bat ball, radio and mobile.
= (1250+ 1105+3250)
= 5605
Raju purchased bucket and mug, almirah and telephone.
= (430+2500+950)
= 3880
Salma purchased hockey stick, radio and mobile.
= (275+ 1105+ 3250)
= 4630.
Reeti purchased bucket, mug, radio and almirah.
= (430+ 1105+ 2500)
=4035
If every person has Rs. 9,500 then what amount of money would be left with each one?
Ans:
Harpal= (9500-7060)= 2440
Dinesh=(9500-5605)= 3895
Raju= (9500-3880)= 5620
Salma= (9500- 4630)= 4870
Reeti= (9500-4035)= 5465
Now tell –
1.) Who has spent more: Harpal or Dinesh ?
= Harpal.
2.) Who has spent more: Dinesh or Reeti ? By how much ?
= Dinesh. 1570.
3.) What is the total amount spent by Raju and Salma both?
= 8510.
4.) How much less was spent by Salma than Harpal?
= 2430.
Now tell the calculated and the actual total
1.) 47, 81
Number | Nearest Tens |
47 | 50 |
81 | 80 |
Calculated Total
5 | 0 | |
+ + | 8 | 0 |
1 | 3 | 0 |
Actual Total
4 | 7 | |
+ + | 8 | 1 |
1 | 2 | 8 |
2.) 67, 32
Number | Nearest Tens |
67 | 70 |
32 | 30 |
Calculated Total
7 | 0 | |
+ + | 3 | 0 |
1 | 0 | 0 |
Actual Total
6 | 7 | |
+ + | 3 | 2 |
9 | 9 |
3.) 97, 15
Number | Nearest Tens |
97 | 100 |
15 | 20 |
Calculated Total
1 | 0 | 0 |
+ | 2 | 0 |
1 | 2 | 0 |
Actual Total
9 | 7 | |
+ + | 1 | 5 |
1 | 1 | 2 |
4.) 72, 138
Number | Nearest Tens |
72 | 70 |
138 | 140 |
Calculated Total
1 | 4 | 0 |
+ | 7 | 0 |
2 | 1 | 0 |
Actual Total
1 | 3 | 8 |
+ + | 7 | 2 |
2 | 1 | 0 |
5.) 8251, 1310
Number | Nearest Thousand |
8251 | 8000 |
1310 | 1000 |
Calculated Total
8 | 0 | 0 | 0 | |
+ | 1 | 0 | 0 | 0 |
9 | 0 | 0 | 0 |
Actual Total
8 | 2 | 5 | 1 | |
+ | 1 | 3 | 1 | 0 |
9 | 5 | 6 | 1 |
6.) 5371, 3800
Number | Nearest Thousand |
5371 | 5000 |
3800 | 4000 |
Calculated Total
5 | 0 | 0 | 0 | |
+ | 4 | 0 | 0 | 0 |
9 | 0 | 0 | 0 |
Actual Total
5 | 3 | 7 | 1 | |
+ | 3 | 8 | 0 | 0 |
9 | 1 | 7 | 1 |
7.) 7214, 1818
Number | Nearest Thousand |
7214 | 7000 |
1818 | 2000 |
Calculated Total
7 | 0 | 0 | 0 | |
+ | 2 | 0 | 0 | 0 |
9 | 0 | 0 | 0 |
Actual Total
7 | 2 | 1 | 4 | |
+ | 1 | 8 | 1 | 8 |
9 | 0 | 3 | 2 |
8.) 632, 225
Number | Nearest Hundred |
632 | 600 |
225 | 200 |
Calculated Total
6 | 0 | 0 | |
+ | 2 | 0 | 0 |
8 | 0 | 0 |
Actual Total
6 | 3 | 2 | |
+ | 2 | 2 | 5 |
8 | 5 | 7 |
9.) 5990, 4137
Number | Nearest Thousand |
5990 | 6000 |
4137 | 4000 |
Calculated Total
6 | 0 | 0 | 0 | |
+ | 4 | 0 | 0 | 0 |
1 | 0 | 0 | 0 | 0 |
Actual Total
5 | 9 | 9 | 0 | |
+ | 4 | 1 | 3 | 7 |
1 | 0 | 1 | 2 | 7 |
10.) 265, 381
Number | Nearest Hundred |
265 | 300 |
381 | 400 |
Calculated Total
3 | 0 | 0 | |
+ | 4 | 0 | 0 |
7 | 0 | 0 |
Actual Total
2 | 6 | 5 | |
+ | 3 | 8 | 1 |
6 | 4 | 6 |
11.) 703, 581
Number | Nearest Hundred |
703 | 700 |
581 | 600 |
Calculated Total
7 | 0 | 0 | |
+ | 6 | 0 | 0 |
1 | 3 | 0 | 0 |
Actual Total
7 | 0 | 3 | |
+ | 5 | 8 | 1 |
1 | 2 | 8 | 4 |
12.) 6410, 3817
Number | Nearest Thousand |
6410 | 6000 |
3817 | 4000 |
Calculated Total
6 | 0 | 0 | 0 | |
+ | 4 | 0 | 0 | 0 |
1 | 0 | 0 | 0 | 0 |
Actual Total
6 | 4 | 1 | 0 | |
+ | 3 | 8 | 1 | 7 |
1 | 0 | 2 | 2 | 7 |
Methods of Vedic Maths
Q.) 1 – What are the digits that are used for writing numbers?
= 0,1,2,3,4,5,6,7,8,9,10.
Q.) 2 – Write the Bijank of following numbers.
(i) 12
Bijank of 12
(1+2)
= 3
So the Bijank of 12 is 3
(ii) 15
Bijank of 15
(1+5)
= 6
So the Bijank of 15 is 6
(iii) 17
Bijank of 17
(1+7)
=8
So the Bijank of 17 is 8
(iv) 19
Bijank of 19
(1+ 0)
=1
So the Bijank of 19 is 1
(v) 37
Bijank of 37
= 3+7= 10
=1+0=1
So the Bijank of 37 is 1
(vi) 44
Bijank of 44
(4+4)
=8
So the Bijank of 44 is 8
(vii) 56
Bijank of 56
(5+6)
=11 (1+1)= 2
So the Bijank of 56 is 2
(viii) 67
Bijank of 67
(6+7)
=13
(1+3)
=4
So the Bijank of 67 is 4
(ix) 96
Bijank of 96
(9+6)
= 15
(1+5)
=6
So the Bijank of 96 is 6
(x) 183
Bijank of 183
(1+8+3)
= 12
(1+2)
= 3
So the Bijank of 183 is 3
(i) 2
2 + 8= 10
So 2 is ParamMitra of 8
And 8 is ParamMitra of 2
(ii) 3
3+ 7=10
So 3 is ParamMitra of 7
And 7 is ParamMitra of 3
(iii) 4
4 + 6=10
So 4 is ParamMitra of 6
And 6 is ParamMitra of 4
(iv) 5
5+5=10
So 5 is ParamMitra of 5
And 5 is ParamMitra of 5
Now tell –
What numbers will you get from the following numbers by doing its Ekadhik twice?
(i) 22
We get 23 by doing Ekadhik of 22 and 24 when we again do Ekadhik of 23 that is get 24 when we do Ekadhik of 22 twice.
(ii) 43
We get 44 by doing Ekadhik of 43 and 45 when we again do Ekadhik of 44 that is get 45 when we do Ekadhik of 43 twice.
(iii) 30
We get 31 by doing Ekadhik of 30 and 32 when we again do Ekadhik of 31 that is get 32 when we do Ekadhik of 30 twice.
(iv) 58
We get 59 by doing Ekadhik of 58 and 60 when we again do Ekadhik of 59 that is get 60 when we do Ekadhik of 58 twice.
What numbers we will get when we do Ekadhik of these numbers thrice?
(i) 23
We get 24 by doing Ekadhik of 23, then we get 25 by doing ekadhik of 24 again and 26 when we again do Ekadhik of 25 that is get 26 when we do Ekadhik of 23 thrice.
(ii) 15
We get 16 by doing Ekadhik of 15, then we get 17 by doing ekadhik of 16 again and 18 when we again do Ekadhik of 17 that is get 18 when we do Ekadhik of 15 thrice.
(iii) 36
We get 37 by doing Ekadhik of 36, then we get 38 by doing ekadhik of 37 again and 39 when we again do Ekadhik of 38 that is get 39 when we do Ekadhik of 36 thrice.
(iv) 42
We get 43 by doing Ekadhik of 42, then we get 44 by doing ekadhik of 43 again and 45 when we again do Ekadhik of 44 that is get 45 when we do Ekadhik of 42 thrice.
Now tell –
What numbers will you get by doing EkNyunen twice?
The meaning of EkNyunenPoorven is take one less than the previous number.
(i) 16
EkNyunen twice of 16 is 14
(ii) 30
EkNyunen twice of 30 is 28
(iii) 67
EkNyunen twice of 67 is 65
(iv) 75
EkNyunen twice of 75 is 73
Similarly practice addition with the help of ParamMitra.
(i) 7 + 8
7 | |
+ | 8 |
Here we have to add 7 and 8. ParamMitraAnk of 7 is 3.
So we taken 3 from 8 and add it to 7.
Now 7+3=10
And taking out 3 from 8 makes it 5. By adding 5 to 10, we get 15
7 | |
+ | 8 |
1 | 5 |
(ii) 8 + 6
8 | |
+ | 6 |
Here we have to add 8 and 6. ParamMitraAnk of 8 is 2.
So we taken 2 from 6 and add it to 8.
Now 8+2=10
And taking out 2 from 6 makes it 4. By adding 4 to 10, we get 14.
8 | |
+ | 6 |
1 | 4 |
(iii) 9 + 8
9 | |
+ | 8 |
Here we have to add 9 and 8. ParamMitraAnk of 9 is 1.
So we taken 1 from 8 and add it to 9.
Now 9+1=10
And taking out 1 from 8 makes it 7. By adding 7 to 10, we get 17.
9 | |
+ | 8 |
1 | 7 |
(iv) 6 + 9
6 | |
+ | 9 |
Here we have to add 6 and 9. ParamMitraAnk of 6 is 4.
So we taken 4 from 9 and add it to 6.
Now 6+4= 10
And taking out 4 from 9 makes it 5. By adding 5 to 10, we get 15.
6 | |
+ | 9 |
1 | 5 |
Also See: Previous chapter 1 ‘Numbers’ full solutions
The post Chhattisgarh Class 4 Math Addition and Subtraction Solution appeared first on Net Explanations.
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]]>Get NCERT Class 6 Social Science 13th chapter ‘The Value of Work’ solutions. This new NCERT book solutions will help students.
Page 187
When Kabir’s grandfather voluntarily teaches the neighbourhood kids for free, is that an economic activity or a non-economic activity? How is it different from your teachers teaching you at school? Discuss with your classmates.
Ans. When Kabir’s grandfather voluntarily teaches the neighborhood kids for free, It is not an economic activity.
We know the activity that performed in exchange of money is called economic activity and the activity that is not involve money is called Non economic activity.
My school teachers teach us and get salary. So it is an economic activity. Whereas Kabir’s grandfather teaches neighborhood kid but not get any salary, here it is non economic activity. They both teaches kids but one is for money and other is for free. This is how teaching of Kabir’s grandfather different from our school teacher.
What are some non-economic activities that are important to you and your family? Why are they valuable?
Ans. There are many non economic activities that are important to me and my family. Every morning I filled all the water bottles and that is important to me and my family. I help my mother while cleaning the house, it is a non economic activity but important. In every evening it is my duty to make tea for me and my family. For this work I am not getting money but it important. These are some of my Non economic activity. Although I do these activities for free but also it is important and valuable to me and my family. So I have to do.
My other no economic activities are—
a.) I plant some flowers for home decoration.
b.) I teach my brother for free. This is also important.
Page 189
On your way from home to school today, can you recall the various economic activities that people are engaged in? In what ways do you think those people are paid?
Ans. From my home to school I saw many economic activities. These are
a.) I saw the road was constructed by many machines and labours. All the labors worked there for money.
b.) Many auto drivers waited for passengers. They took the passengers and went to their destination for money.
c.) Also I noticed some hawkers sells some product in exchange of money.
Page 193
Many communities in India have similar practices that involve community participation. Can you identify a few from your area?
Ans. In my area I notice many community participation. Some community celebrate “Van Mahotsav” is a festival of forest to promotes awareness about the important and value of trees.
Some community celebrates “Ganga snan”. They clean Local river and do a Puja.
Some community celebrates “Agni”. They stop the uses of fire for one day.
We celebrate many festivals in India. During these festivals, people gather to organise all the various activities. They decorate the place together and share the food that they cook. Are these non-economic activities?
Ans. Yes . It is non economic activities.
We celebrate many festivals in India. During these festivals, People gather to organize all various activity Without expecting anything in return. We decorate the place and share the food that we make for Self satisfaction and gratitude. So its hold a value.
Can you identify community programmes that have been undertaken by your school or in your locality? What did you observe during these programmes?
Ans. In our area I saw a community program that is “Ganga Puja”.
In this program We clean our house surrounding individually. People have also came together to clean up streets, roads, park, rivers, pond and other public places. Together this effort leads to a clean home, neighborhoods and river. Then the people of our village do a puja at the bank of local river.
Questions, activities and projects
1.) How are economic activities different from non-economic activities?
The activity that is performed in exchange of money is called economic activity. And the activity that is performed for, satisfaction gratitude and without expecting anything in return is called Non economic activity. That is the reason why Economic activity is different from non economic activity.
2.) What kind of economic activities do people engage in? Illustrate with examples.
The activity that involves money is called economic activity. People engage in many economic activity. The teachers of school teaches students and get salary. The hawkers sells their goods in exchange of money. The workers of construction site do their job for money. And there are so many economic activity that people engage in.
3. ) There is great value attached to people who are engaged in community service activities. Comment on this statement.
People attached to many community activity such a “Swach Bharat abhiyan’’,”vana mahatsav” and so on. In this activity people individually clean their home and surrounding. People also came together to clean the roads, parks public area. People plant many trees for better world. So it has a great value of community program.
4.) What are the various ways in which people are compensated for various economic activities? Give some examples
People are compensated in various way such as school teacher teaches student in school and get salary. Workers of construction site are worked for money. Hawkers sells their good in exchange of money. Loco pilot of train and jet are get salary for their job. Indian army protect our country also an economic activity because it involves money. And there are so many way that people are compensated for various economic activity.
Also See: NCERT Class 6 Social Science Chapter 2 Inside Questions and Answers
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