Factorisation MCQ Questions Class 8 Maths Chapter 14
Chapter 14
Factorisation
Question 1:
Find the common factors in 4x2, 36x
(a) 9x
(b) 4x
(c) 2x
(d) 3x
Ans:
4x2 = 4 × x × x
36x = 4 × 9 × x
(b) 4x is the common factor.
Question 2:
Find the common factors in 15y, 60y2
(a) 9y
(b) 3y
(c) 15y
(d) 4y
Ans:
15y = 15×y
60y2 = 15 × 4 × y × y
(c) 15y is the common factor
Question 3:
Factorise x3 + 2xy + 3x2 + 4x
(a) y (x2 + y + 4)
(b) x (x + y + 4)
(c) y2 (x – 4)
(d) x (x2 + 2y + 3x + 4)
Ans:
x3 + 2xy + 3x3 + 4x
= (x × x × x) + (2 × x × y) + (3 × x × x) + (4 × y)
= x (x2 + 2y + 3x + 4) (d)
Question 4:
Factorise 5x – 25x2
(a) 5x (1 – 5x)
(b) 5x (1 – 2)
(c) 2x
(d) 5x2
Ans:
= 5 × x – 5 × 5 × x × x
= 5x (1 – 5x) (a)
Question 5:
Factorise x2 + 6x + 9
(a) (x – 3)2
(b) (x + 3)2
(c) (x + 3)3
(d) x – 3
Ans:
= x2 + 6x + 9
= x2 + 3 × x × 2 + 32
= (x + 3)2 (b)
Question 6:
Factorise 4y2 – 12y + 9
(a) (2y – 3)2
(b) (2y + 3)2
(c) 2y – 3
(d) 2y + 3
Ans:
= 4y2 – 12y + 9
= 22y2 – 3 × 2 × 2 × y + 32
= (2y – 3)2 (a)
Question 7:
Factorise n2 – 36
(a) n + 6
(b) (n – 6) (n + 6)
(c) n – 6
(d) 6 + n
Ans:
n2 – 36
= (n + 6) (n – 6) (b)
- In case you have missed:- Previous Chapter MCQ Questions
Question 8:
Find the factors of x2 – 11x + 28
(a) (x – 7)2
(b) (x + 4)2
(c) (x – 4) (x – 7)
(d) (x + 4) (x – 7)
Ans:
28 = (-7) × (-4) and (-7) + (-4) = -11
28 = 7 × 4 and 7 + 4 = 11
x2 – 11x + 28 = x2 – 7x – 4x + 28
= x (x – 7) – 4 (x – 7)
= (x – 4) (x – 7) (c)
Question 9:
Factorise 25m2 – 36n2
(a) 5m + 6n
(b) 5m – 6n
(c) (5m – 6n)2
(d) (5m + 6n (5m – 6n)
Ans:
25m2 – 36n2
= 52m2 – 62n2
(d) = (5m + 6n) (5m – 6n)
Question 10:
Factorise 6y2 + 2y + 3y3
(a) (2 + y)2
(b) (2 – y)3
(c) 2 + 3 (2 + y)
(d) y [2 + 3 (2 + y)]
Ans:
6y2 + 2y + 3y3
= (3 × 2 × y × y) + 2 × y + (3 × y × y × y)
= y (6y + 2 + 3y2)
= y [2 + 3 (2 + y)] (d)
Question 11:
9x2, 6xy find the common factor
(a) 2x
(b) 4x
(c) 3x
(d) 3x2
Ans
(c) 3x is the common factor.
Question 12:
Carry out the division 81 x2 y ÷ 9x
(a) x2 y
(b) 3x2 y
(c) 9x y
(d) 9x2 y
Ans:
81x2 y/9x = 9×9×x×x×y/9×x
(c) = 9xy
Question 13:
Find solution in x3 + 3x + 2 for x = 2
(a) 12
(b) 16
(c) 18
(d) 14
Ans:
x3 + 3x + 2 for x = 2
(2)3+ 3 × 2 + 2
8 + 6 + 2 = 16 (b)
Question 14:
Divide as directed
256 x2 – 169 y2 ÷ (16x – 13y)
(a) 16x + 13y
(b) 13y – 16x
(c) 16x – 13y
(d) 13y + 6
Ans:
Question 15:
If 40 y6 is a multiple of 4, where y is a digit, what might be the value of y?
(a) 11
(b) 10
(c) 9
(d) 7
Ans:
When we put y = 9 then we get the 4096÷4 = 1024
y = 9 (c)
- In case you have missed:- Next Chapter MCQ Questions
Here is your solution of NCERT Factorisation MCQ Questions Class 8 Maths Chapter 14
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