Chhattisgarh State Board Class 9 Science Chapter 2 Matter : Nature and Behaviour Exercise Multiple Choice, Fill in the Blanks, Questions and Answers here.
Chhattisgarh State Class 9 Science Chapter 2 Solution
1) Choose the correct option:
(i) Homogeneous mixture is:
(a) iron (b) bronze
(c) 24 carat gold (d) oxygen.
Ans: – option (c) 24 carat gold.
(ii) Heterogeneous mixture is
(a) pure water (b) concrete
(c) solution of salt in water (d) lime (calcium oxide).
Ans: – (c) solution of salt water.
(iii) Oxygen is
(a) an element (b) a compound
(c) a heterogeneous mixture (d) a homogeneous mixture.
Ans: – option is (a) an element.
(iv) Sugar is
(a) an element (b) a compound
(c) a heterogeneous mixture (d) a homogeneous mixture.
Ans: – option (d) a homogeneous mixture.
(v) Which of the following will show Tyndall effect
(a) solution of salt in water (b) starch solution
(c) solution of baking soda in water (d) vinegar.
Ans: – option (b) starch solution.
(vi) Which of the following is not a pure substance
(a) ice (b) iron
(c) mercury (d) milk.
Ans: – except milk all are pure.
2) Choose solutions from the given mixtures –
soil, sea water, air, soda water, mixture of glue in water, mixture of milk in water.
Ans: – Homogeneous solution are sea water, air, soda water.
Heterogeneous solution is soil.
3) Separate the following into elements, mixtures and compounds –lemonade, rocks, copper, diamond, salt, neon gas, salad, pure water, aluminium, silver, soap, blood, carbon dioxide, sodium.
Ans: – Element: – neon, copper, aluminium, sodium.
Mixture: – lemonade, rocks, salad, soap, blood.
Compound: – diamond, pure water, carbon dioxide.
4) Choose the appropriate option to fill in the blanks:
(i) An element has ………same………………… type of particles (same/different).
(ii) The scattering of light by colloid particles is called ………… Tyndall………………….. (Tyndall effect/Brownian motion).
(iii) In tincture iodine solution, iodine is the …solute……………………. (solvent/ solute).
(iv) The particles in a ………. suspension……………….. can be separated by filtration using filter paper. (suspension/ colloid).
(v) Particles in a ………. solution…………………………… cannot be seen with the naked eye (solution/suspension).
5) Explain the following with examples –
Pure substances, saturated solutions, colloid, suspension.
Ans: – Pure solution:- If there is only one type of element in any solution then this solution is known as pure solution. Example: – distilled solution.
Saturated solution: – By applying temperature if the more amount of solute is dissolve in any solution, then this solution is known as saturated solution.
Colloidal solution: – In any solution the particles cannot be seen by naked eyes and there are present small tiny particles makes this solution colloidal in nature. Example: – milk.
Suspension: – In suspension the particles are seen in naked eyes. As the chalk powder seen in naked eyes this is an example of suspension.
6) Through an activity, demonstrate that the sugar dissolved in water is a solution.
Ans: – If we take some amount of water then put some sugar in that. After sometimes we will see that there are no any sugar particles. This sugar particles as dissolve we don’t see any particles.
7) What is the effect of temperature on the solubility of a solid in a liquid? Explain through an activity.
Ans: – In any after adding some solute we will see that the solute remains under after mixing after some amount. At this time if we apply some temperature then we will see that solubility of the solute in that solution Will increase so the effect of temperature is clearly seen. This type of phenomenon we can see in sugar solution.
8) Write the differences between solutions, colloids and suspensions.
Ans: –
Solution | colloids | Suspension |
Homogeneous mixture | Heterogeneous mixture | Heterogeneous mixture |
Particles cannot see in naked eyes. | Particles cannot see in naked eyes. | Particles can be seen in naked eyes |
Distilled water is example of solution. | Milk seen colloidal solution | Chalk powder is the example of suspension. |
9) How will you differentiate between homogeneous and heterogeneous mixtures?
Ans: –
Homogeneous mixture | Heterogeneous mixture |
Same type of element are seen. | Different types of elements are seen |
Particles can’t be seen easily | Particles can be seen easily. |
Separation of particles is not possible. | Separation of particles is possible |
10) Seema took three solids, A, B and C and made their saturated solutions in 100 g water at differenttemperatures. The amounts of A, B and C used to form saturated solutions are shown in the table:
solute | Temperature in K | |||
293K | 313k | 333K | 353k | |
a | 35g | 36g | 37g | 38g |
b | 32g | 62g | 106g | 167g |
c | 34g | 40g | 46g | 54g |
(i) What are the amounts of A, B and C needed to form saturated solutions at 293 K? Whatcan you conclude based on this observation?
(ii) Calculate the amount of solutes A, B and C needed to form saturated solutions in 500 gwater at 313 K.
(iii) Find the concentration in mass percent of A and C at 353 K.