Chhattisgarh State Board Class 9 Science Chapter 15 Hydrocarbons Exercise Multiple Choice, Fill in the Blanks, Questions and Answers here.
Chhattisgarh State Class 9 Science Chapter 15 Solution
1) Choose the correct option that fits the descriptions given below:-
(i) This hydrocarbon only has single bonds.
Ans: – Alkanes.
(ii) Carbon has the ability to form strong bonds with atoms of other elements. But what is morespecial is its ability to bond strongly with other carbon atoms.
Ans: – Chain isomers.
(iii) Molecules having same molecular formula but different structures.
Ans: – Isomers.
(iv) Butane and 2-methylpropane exhibit this type of isomerism.
Ans: – Positional isomers.
(v) Isomerism that can be exhibited by alkenes and alkynes but not alkanes.
Ans: – Catenation.
(vi) Members of this series show a regular gradation in their physical properties.
Ans: – Homologous series.
(Position isomerism, homologous series, alkanes, isomers, chain isomerism, catenation)
2) Fill in the blanks
(i) Hex-1-ene and hex-2-ene are ………positional ……………..isomers.
(ii) The boiling point of butane is ………higher…….than propane.
(iii) The number of carbon atoms in the parent chain of 2-methylpropane…. three….
(iv) The number of hydrogen atoms in cyclobutene is…eight……………
(v) C2H6,C3H8, C4H10 are members of the ……same…………..homologous series.
3) Draw the structures of the following:
2-methylbutane, prop-1-yne, pent-2-ene.
Ans: –
4) Write any three characteristics of the alkane family.
Ans: – The characteristics of alkane are –
- Reactive in nature.
- Oxidation happen in that family element.
- Generally soft and cut through knife.
5) Differentiate between position and chain isomerism with examples.
Ans: –
Positional isomer |
Chain isomers |
In positional isomers the main difference this from the chain isomers is the present of functional group in their structure. |
In chain isomer the same no of structural formula the difference is the carbon in their main chain. |
It is non homologous series. |
It is homologous series. |
6) What is the relation between the boiling points and number of carbon atoms present in straight chainalkane? Explain.
Ans: – The increase in the no of carbon atoms in a compound make the structure cumulatively stronger than the previous one. So, when there is a try to break it, the boiling point increased. So, we can say boiling point is increased with the increased of no of carbon atoms.
7) Alkanes, alkynes and alkenes with three or less carbon atoms do not show structural isomerism. Explain.
Ans: – If any organic compound forms branch it shows structural isomerism. And for an organic compound if the no of carbon atoms less than three it is not capable of forming branches so it doesn’t show the structural isomerism.
8) How many structures/isomers are possible for the molecular formula C4H8? Draw their structures.
Ans: –