Capacitance MCQs
Capacity of capacitor is depends upon the magnitude of charge and the potential difference applied the plates of capacitor.
The charge on conductor increases the potential of conductor. It is found that
Q ∝ V
Q = CV
Where ‘C’ is constant called capacity or capacitance of conductor.
C = Q/V
Capacity of conductor or capacitance can be defined as the quantity of charge required to raise the potential by one unit.
SI unit of capacitance is farad (F).
The formula for capacitance in terms of dielectric constant, area of plates and distance between the plates is given as,
Q.1) The capacity of capacitor is directly proportional to….
a) magnitude of charge accumulated on its plate
b) distance between the plates
c) potential difference applied across the plates
d) all of these
Q.2) The capacitance of capacitor is 10 µF in air, what will be its capacitance if a marble slab of dielectric constant 7 is kept between the plates?
a) 10/7 µF
b) 7/10 µF
b) 70 µF
d) 10 µF
Q.3) Capacitance of capacitor if its area of plates and distance between plates is doubled is……..
a) C
b) 2C
c) C/2
d) None of these
Q.4) The ratio of capacitance of capacitance of plates of equal area and equal separation with dielectric materials of dielectric constant 3 and 6 is….
a) 1:1
b) 2:1
c) 1:2
d) None of these
Q.5) Capacitance of capacitor with the total charges 16 µC, connected across the potential difference of 4 V is…
a) ¼ µF
b) 4 µF
c) ½ µF
d) 2 µF
Q.6) SI unit of Capacitance is named after….
a) J C Maxwell
b) H C Oerstad
c) C F Gauss
d) Michael Faraday
Q.7) Capacity of capacitor can be decreased by……
a) increasing dielectric constant.
b) increasing area of plates.
c) decreasing distance between the plates.
d) increasing the distance between the plates.
Q.8) If the gap between plates of capacitor is filled with conducting material, the capacitance of capacitor will be….
a) increases
b) decreases
c) remains same.
d) becomes zero.
Answers
Q.1) a) magnitude of charge accumulated on its plate
Q.2) b) 70 µF
Q.3) a) C
Q.4) c) 1:2
Q.5) b) 4 µF
Q.6) d) Michael Faraday
Q.7) d) increasing the distance between the plates.
Q.8) d) becomes zero.
