Assam SCERT Class 5 Maths Chapter 14 Use of Measurements Question Answer Solution
Assam Board Class 5 Maths Chapter 14 Use of Measurements all Question’s easy Solution by expert teachers. Assam SCERT Class 5 Maths Chapter 14 Use of Measurements Solution.
Board |
Assam SCERT |
Class |
5 |
Book |
New Mathematics Part 5 |
Topic |
Question answer |
1.) Answer the following.
a.) How much time did Pritam and his father need for marketing?
..1..hr 30 min.
b.) What was the total length of the cloth for window cartain?
1.5 meter.
c.) What was the total weight of the items bought by the unit of weight?
3 kg 750 gm.
d.) What is the total volume of the items bought with the unit of volume?
1.5 Ltr.
2.) Add the following.
a.) 5 m 34 cm, 8 m 50 cm, 2 m
Solution –
5 m 34 cm
+ 8 m 50 cm
+ 2 m 00 cm
_____________________
15 m 84 cm or 15.84 cm.
a.) 6 m 35 cm, 7 m 45 cm
Solution –
6 m 35 cm
+ 7 m 45 cm
________________________
13 m 80 cm or 13.80 cm.
b.) 18 km 70 m, 15 km, 23 km 378 m
Solution –
18 km 70 m
+ 15 km 00m
+ 23 km 378m
___________________
56 m 448 m or 56.448 m.
c.) 8kg 732 gm, 35 kg 690 gm
Solution –
8 kg 732 gm
+ 35 kg 690 gm
____________________
43 kg 1422 gm or 43.1422 gm.
d.) 4 ltr 500 ml, 12 ltr 750 ml
Solution –
4 ltr 500 ml
+ 12 ltr 750 ml
_________________
16 ltr 1250 ml or 16.1250 ml.
e.) 250 ml,17 ltr 350 ml, 8 ltr 50 ml
Solution –
3.) Subtract the following.
1.) 7 mtr 30 cm from 15 mtr 40 cm
Solution – 15 mtr 40 cm – 7 mtr 30 cm
= 8 mtr 10 cm.
2.) 7 m 50 cm from 10 m 80 cm
Solution – 10 m 80 cm – 7 m 50 cm
= 3 m 30 cm.
3.) 9 m from 14 m 30 cm
Solution – 14 m 30 cm – 9 m 00 cm
=5 m 30 cm.
4.) 110 gm from 160 gm
Solution – 160 gm – 110 gm
= 50 gm.
5.) 5 kilogram 105 gram from 7 kilogram 250 gram
Solution – 7 kg 250 gm – 5 kg 105 gm
= 2 kg 145 gm.
6.) 6.250 kilogram from 12.500 kilogram
Solution – 12.5 kg – 6.25 kg
=6.25 kg.
7.) 2 ltr 500 ml from 3 ltr 900 ml
Solution – 3 ltr 900 mi – 2 ltr 500 ml
= 1 ltr 400 ml.
4.) Find the following.
1.) From whose home is the distance of the school minimum?
Ans. – House of Nikita.
2.) Sneha takes 20 minutes to go to school direct. If she goes via Niharika’s house, wheather she will take more or less time?
Solution – She will take more time.
3.) Between Niharika and Nikita, whose home is the distance to school maximum? Is it of Niharika or Nikita?
Solution – Niharika’s.
4.) If Niharika and Nikita come to Sneha’s home to play, who will have to walk more and how much?
Solution – Nikita have to walk 400 meter more.
5.) Solve the following.
1.) The distance from Madhurjya’s home to his maternal uncle is 52 km walking 0.75 km from his home, 5.25 km by E-Rickshaw and the remaining part by bus Madhurjya reaches his maternal uncle’s house. How much distance does he travel by bus?
Solution – Total Distance = 52 km.
Distance travelled by walking = 0.75 km.
Distance travelled by E-Rickshaw = 5.25 km.
So,Distance travelled by bus =
=Total Distance – Distance travelled by walking – Distance travelled by E-Rickshaw .
Distance travelled by bus = 52 km – 0.75 km – 5.25 km.
= 46 km.
2.) A piller 4 metres in length is in the middle of a pond. Its 0.5 metres is in mud, 2.25 metres in water. What is the length of the remain- ing part of the piller?
Solution – Total length of piller = 4 m.
Length of piller in mud = 0.5 m
Length of piller in water = 2.25 m.
So, length of the remain- ing part of the piller
= Total length of piller – Length of piller in mud – Length of piller in water.
= 4 m – 0.5 m – 2.25 m.
= 1.25 m.
The length of the remaining part of the piller is 1.25 meter.
3.) Haren’s father cut 6 pillers each 3 metres in length to build a cowshed. What is the total length of the pillers?
Solution –
Total length = Number of pillars × Length of each pillar
Total length = 6 pillars x 3 meters/pillar
Total length = 18 meters.
4.) The circumference of a wheel of a by cycle is 250 cm. Manish travels 1.5 km from his house to school. How much rounds does the wheel make? (Hint: Circumference of a wheel = Distance travelled in one round)
Solution –
1.5 kilometers = 1.5 × 1000 meters = 1500 meters.
Now, we need to find out how many rounds Manish’s wheel makes while traveling 1500 meters.
The circumference of the wheel is given as 250 cm.
So, the number of rounds (N) made by the wheel is calculated using the formula:
N =(Distance travalled)/(Circumference of wheel)
N =(1500 meter x 100)/(250 cm.)
N =150000/(250 )
N = 600 .
So, the wheel makes 600 rounds during Manish’s journey from his house to school.
6.) Solve the following problems related to weight.
1.) What is the total weight of the items Sl. No.1 to 5?
Solution – Total weight = 5 kg + 2 kg + 3 kg +500gm +1 kg
Total weight = 11 kg 500 gm.
2.) What is the total cost of those items?
Solution – Total cost = 150 +140 +60 + 20 +30
Total cost = 400.
3.) According to the table, what is the cost of 5 kg onion ?
Solution – Cost of 1 kg onion= Rs. 40.
Cost of 1 kg onion = 5 x Rs. 40.
= Rs. 200.
4.) What was the total expenditure of Reema’s uncle?
Solution –
Total expenditure = 150 +140 +60 + 20 +30 +750+350+30+25+30.
Total expenditure = Rs.1585.
5.) In the table which items, the price rate is the highiest?
Solution – Fish’s price is highest i.eRs. 750.
7.) Read the following problems and solve.
1.) A bag containing 40 kg and 500 gram rice. How much rice is needed to make it 50 kg?
Solution – Total rice should be 500 kg.
Rice in bag – 40 kg 500 gm = 40.5 kg.
To make it weigh 50 kg, we need 50kg – 40.5 kg
= 9.5 kg more.
Therefore, 9.5 kilograms of rice is needed to make the bag weigh 50 kg.
2.) A tea stall requires 2 gas cylinder (L.P.G.) of weight 14.2 kg in a month. How much total L.P.G. is required in a month in the tea stall?
Solution –
Weight of one gas cylinder = 14.2 kg
Number of cylinders used in a month = 2
Total L.P.G. required = Weight of one gas cylinder × Number of cylinders
= 14.2 kg/cylinder × 2 cylinders
= 28.4 kg
So, the tea stall requires a total of 28.4 kg of L.P.G. in a month.
3.) Pradip wanted to buy 4 apples. The vendor placed 1 kg weight one side and 4 apples another side. Then he placed 100 gm and 50 gm weight with the apples to keep the balance equivalent. Now what is the total weight of the 4 apples that Pradip bought?
Solution –
Given –
1 kg weight is balanced against 4 apples.
100 gm and 50 gm weights are added to the side with the apples to balance the scale.
Since 1 kg is equivalent to 1000 grams, and there are 100 grams and 50 grams added to balance the apples:
Total weight of apples = (1 kg + 100 gm + 50 gm) – 1 kg
= (1000 gm + 100 gm + 50 gm) – 1000 gm
= 1150 gm – 1000 gm
= 150 gm.
So, the total weight of the 4 apples that Pradip bought is 150 grams.
4.) If you divide 4 kg Bundia into packet of 250 gms, what will be the total number of packets?
Solution – 1 kg = 1000 grams
So, 4 kg = 4 * 1000 = 4000 grams.
Now, to find out how many packets of 250 grams each can be made from 4000 grams:
Total number of packets = Total weight / Weight per packet
= 4000 grams / 250 grams
= 16 packets.
Therefore, you can make a total of 16 packets when dividing 4 kg of Bundia into packets of 250 grams each.
5.) One day Juwel goes to buy vegetables. The vendor tells him that he will get 300 gms beans in 10 rupees. But the vendor has 500 gms and 200 gms weight only. Now how will the vendor measure 300 grams beans?
Solution – Here’s a possible approach:
Start with the 500 grams weight.
Subtract 200 grams from 500 grams to get 300 grams.
8.) Solve the following problems related to volume.
1.) Babul brought 2 litres milk from grand uncle, 5 litres from milk- man Ramu and 2 litres and 500 ml from a hotel on his sister’s birthday. How much milk in total did he bring that day?
Solution – 1 liter = 1000 ml
Now, let’s add up all the quantities:
From grand uncle: 2 liters
From milkman Ramu: 5 liters
From the hotel: 2 liters + 0.5 liters = 2.5 liters
Total milk Babul brought = 2 liters + 5 liters + 2.5 liters
= 9.5 liters.
Therefore, Babul brought a total of 9.5 liters of milk on his sister’s birthday.
2.) From a co-operative retail shop Ananda, Fazal, Bipul and Simi bought 3 litres, 2.5 litres, 5 litres and 1.5 litres kerosin oil respec- tively. If there was 20 litres of oil then how much oil will be left in the shop after selling?
Solution –
Given:
Initial amount of oil in the shop = 20 liters
Amount of oil bought by:
Ananda = 3 liters
Fazal = 2.5 liters
Bipul = 5 liters
Simi = 1.5 liters
Total amount of oil bought = 3 liters + 2.5 liters + 5 liters + 1.5 liters
= 12 liters
Now, to find out how much oil will be left in the shop after selling:
Oil left in the shop = Initial amount of oil – Total amount of oil bought
= 20 liters – 12 liters
= 8 liters
Therefore, there will be 8 liters of oil left in the shop after selling.
3.) In a school 47 students of class five drink 2 litres water each. In a day how many litres of water will be required?
Solution –
Given:
Number of students = 47
Amount of water each student drinks = 2 liters
Total amount of water required = Number of students × Amount of water each student drinks
= 47 students × 2 liters/student
= 94 liters
Therefore, in a day, 94 liters of water will be required for the 47 students of class five.
4.) Among 350 participating students of Narayanpur Girls Middle School, lemon water has been distributed equally after the proces- sion taken out in connection with National Education Day. If each student gets 200 ml of lemon water then what was the total amount of lemon water in litres?
Solution –
Given:
Number of participating students = 350
Amount of lemon water each student gets = 200 ml
Total amount of lemon water distributed = Number of students × Amount of lemon water per student
= 350 students × 200 ml/student
= 70000 ml
Now, to convert the total amount of lemon water from milliliters to liters, we divide by 1000 (since 1 liter = 1000 ml):
Total amount of lemon water in liters = 70000 ml ÷ 1000
= 70 liters
Therefore, the total amount of lemon water distributed is 70 liters.
9.) Solve the following problems.
1.) How much time does Amlan spend in school?
Ans – Amlan spends the following time in school:
Morning: 8:45 a.m. to 3:30 p.m.
Time spent in school = 3:30 p.m. – 8:45 a.m.
= 6 hours 45 minutes.
2.) How much time does Amlan get till he starts studying at home in the evening after his school ever?
Ans – Amlan finishes school at 3:30 p.m. and starts studying at home in the evening at 6:30 p.m.
Time till Amlan starts studying at home
= 6:30 p.m. – 3:30 p.m. = 3 hours.
3.) How much time Amlan gets for other work?
Solution – This includes all activities other than studying, sleeping, and being in school.
Time for other work = Total time – (Time spent studying + Time spent sleeping + Time spent in school)
= 24 hours – (4 hours + 8 hours + 6 hours 45 minutes)
= 24 hours – (18 hours 45 minutes)
= 5 hours 15 minutes.
4.) If Amlan goes to bed at 9:30 p.m., when will he get up in the morning?
Solution –
Amlan sleeps for 8 hours at night and goes to bed at 9:30 p.m.
Time Amlan goes to bed = 9:30 p.m.
Time Amlan wakes up = Time Amlan goes to bed + 8 hours
= 9:30 p.m. + 8 hours
= 5:30 a.m.
5.) What fraction of time of a day does Amlan spend in reading at home?
Solution – Total time spent in reading at home = 12 hours (from question 1)
Total time in a day = 24 hours
Fraction of time spent in reading at home = (12 hours) / (24 hours) = ½.
6.) What fraction of time of a day does Amlan use in sleeping?
Solution –
Total time spent sleeping = 8 hours (night)
Total time in a day = 24 hours
Fraction of time spent sleeping = (8 hours) / (24 hours) = 1/3.