AP SSC 10th Class Physical Science Chapter 7 Solution – Human Eye and Colourful world
Andhra Pradesh SSC 10th Class Physical Science Chapter 7 Human Eye and Colourful world Solution for AP SSC 10th Class Physics/Chemistry Exam. Lots of Students of Andhra Pradesh Board will search on internet for Andhra Pradesh Class 10 Physical Science Textbook Solution or Study Material for AP SSC 10th exam. Here you search will end! Here in this page we have provided for all question answer for Chapter 7 Human Eye and Colourful world.
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AP 10th Class Physics Chapter 7 Human Eye and Colourful world Solution
(1) How do you correct the eye defect Myopia? (AS1)
Ans: –By using concave lense we can correct the defect myopia.
(2) Explain the correction of the eye defect Hypermetropia. (AS1)
Ans: –The eye defect hypermetropia can be cured by using convex lense.
(3) How do you find experimentally the refractive index of material of a prism? (AS1)
Ans:-
The refractive index of material of prism is Sin(A+ D/2)×SinA/2. Where A= angel of prism and D= angel of deviation.
(4) Explain the formation of rainbow. (AS1)
Ans: –When at the opposite of sun sometimes we see different colours at a time in the sky we called this phenomenon rainbow. This is happened because of the reflection, refraction and dispersion of different light water droplets.
(5) Explain briefly the reason for the blue of the sky. (AS1)
Ans: –The different particles present in the earth atmosphere scattered the sunlight. In sunlight although various colour present only blue light scattered more and for this reason we see sky is blue.
(6) Explain two activities for the formation of artificial rainbow. (AS1)
Ans: –In a glass prism when sunlight fallen in it we seen rainbow like phenomenon. The another way to form artificial rainbow is a glass of water filled with water and a mirror is placed besides it , there should be a white paper under the glass. Now see the mirror through the glass upper surface.
(7) Derive an expression for the refractive index of the material of a prism. (AS1)
Ans: – IMG
(8) Light of wavelength λ1 enters a medium with refractive index n2 from a medium with refractive index n1. What is the wavelength of light in second medium?
Ans: –As we know refractive index = velocity in the air/ velocity in that medium. So let take velocity of different medium be v1 and v2. C= Velocity in air
Then n1= C/v1 and n2= C/ n2
By comparing the value of C we get v1/v2=n2/n1.
According to formula v1= y1 × f (f= frequency), and v2= y2×f
By comparing the value of f we get, v1/v2 = y1/y2
Or n2/n1= y1/y2; or y2= (n1/n2) y1
(9) Assertion (A): The refractive index of a prism depends only on the kind of glass of which it is made of and the colour of light. (AS 2)
Reason (R): The refractive index of a prism depends on the refracting angle of the prism and the angle of minimum deviation.
Ans: –(a) Both A and R are true and R is the wright explanation of A. As the refractive index of different material are different then angel of the prism of different material be different.
(10) Assertion (A): Blue colour of sky appears due to scattering of light.
Reason (R): Blue colour has shortest wavelength among all colours of white light. (AS 2)
Ans: –(c) A is correct but R is false. In different colours of sunlight only blue light scattered most by atmospheric particle so the sky looks blue.
(11) Suggest an experiment to produce a rainbow in your classroom and explain the procedure. (AS 3)
Ans: –At first stand in front of a white wall try wall be white in colour. Take pipe flowing water through it then hold some water by your finger leave some amount. When this water will flow in front of wall like fountain then you see the rainbow in the showering water.
(12) Prisms are used in binoculars. Collect information why prisms are used in binoculars. (AS4)
Ans: –With the help of prism the image being erected which are formed by binoculars. The optical path of the binoculars reduce by prism. For these reason prism are used in binoculars.
(13) Incident ray on one of the face (AB) of a prism and emergent ray from the face AC are given in figure Q-13. Complete the ray diagram. (AS 5)
Ans: –
(14) How do you appreciate the role of molecules in the atmosphere for the blue colour of the sky? (AS 6)
Ans: –The blue colour scattered most as compare to any other colours present in the atmosphere. Different particles in atmosphere reflect blue light most for these reason the sky is blue.
(15) Eye is the only organ to visualize the colourful world around us. This is possible due to accommodation of eye lens. Prepare a six line stanza expressing your wonderful feelings. (AS 6)
Ans:-
- I always want to this colourful world.
- The rainbow view in hilly are marvelous.
- It such a nice village.
- The flowers in the garden are beautiful.
- The cloud above the hills makes it more beautiful.
- These forest is wonderful.
(16) How do you appreciate the working of ciliary muscles in the eye? (AS 6)
Ans: –Ciliary muscles in our eye help to maintain the focal length of our eye lense. It sometimes get relaxed or crunch according to our focusing on any object.
(17) Why does the sky sometimes appear white? (AS 7)
Ans: –The water vapour present in the atmosphere scattered other colours than blue. For this scattering the white colour of water molecules are seen. This phenomenon are mostly seen due to high temperature in sunny day.
(18) Glass is known to be a transparent material. But ground glass is opaque and white in colour. Why? (AS 7)
Ans: –Ground glass is a translucent object of frosted glass so it doesn’t reflect any light rays. So for this property of ground glass is white in colour.
(20) If a white sheet of paper is stained with oil, the paper turns transparent. Why? (AS 7)
Ans: –As the oil and the paper have same refractive index it fill the gap between the papers and it so light rays easily transmitted. For this property of oil the paper turns transparent.
(21) The focal length of a lens suggested to a person with Hypermetropia is 100cm. Find the distance of near point and power of the lens.
Ans: –According to the formula f=25d/(d-25) cm. Here f=100cm; so d= 100/3=33.33
The distance of near point is 33.33cm.
The power is P=1/f × D (here f in m)
So; P= 1/100×10^-2=1D
The power of the lense is 1D.
(22) A person is viewing an extended object. If a converging lens is placed in front of his eye, will he feel that the size of object has increased? Why? (AS7)
Ans: –As we all know that the converging lense always produce the virtual image of any object. So if a converging lens kept in front of his eyes he will see the object bigger than its normal size. The image will be magnified and upright which helps to view easier to the object.
FILL IN THE BLANKS
(1) The value of least distance of distinct vision is about ……25cm………
(2) The distance between the eye lens and retina is about…..2cm………….
(3) The maximum focal length of the eye lens is about…..2.5cm………….
(4) The eye lens can change its focal length due to working of….. ciliary…………… muscles.
(5) The power of lens is 1D then focal length is …100cm………
(6) Myopia can be corrected by using ………concave…………………. lens.
(7) Hypermetropia can be corrected by using ……….convex………………… lens.
(8) In minimum deviation position of prism, the angle of incidence is equal to angle of …emergence……….
(9) The splitting of white light into different colours (VIBGYOR) is called… dispersion of white light………….
(10) During refraction of light, the character of light which does not change is … wavelength and frequency………..
MULTIPLE CHOICE EQUATION
(1) The size of an object as perceived by an eye depends primarily on. – (d) size if the image formed on the retina.
(2) When objects at different distances are seen by the eye which of the following remain constant? (C) the radii of curvature of eye lense.
(3) During refraction, ___frequency_____ will not change.
(4) A ray of light falls on one of the lateral surface of an equilateral glass prism placed on the
(5) horizontal surface of a table as shown in fig. MCQ-4. For minimum deviation of ray, which of the following is true? –(b) QR is horizontal.
(6) The process of re-emission of absorbed light in all directions with different intensities by the
(7) atom or molecule is called … scattering of light……
