Algebraic Expressions and Identities MCQ Questions Class 8 Maths Chapter 9

Algebraic Expressions and Identities MCQ Questions Class 8 Maths Chapter 9

NCERT MCQ Questions for Class 8 Maths Chapter 9 Algebraic Expressions and Identities. Algebraic Expressions and Identities MCQ Questions with Answers from Class 8 Maths.

Algebraic Expressions and Identities MCQ Questions Class 8 Maths Chapter 9

Algebraic Expressions and Identities Multiple Choice Questions with Answers Class 8 Maths Chapter 9 PDF is available.

Question 1:

Identify the coefficient of xy2

xy – 4xy2 – 5x2y

(a) -5

(b) 5

(c) (-4)

(d) 4

Ans:

xy – 4xy2 – 5xy2 = 0

(-4) xy2 = Coefficient (-4) (c)

 

Question 2:

Identify the coefficient of y2, x – y2 – 2xy2 + 100

(a) 2

(b) -1

(c) 1

(d) -2

Ans:

x – y2 – 2xy2 + 1 = 0

(-1) y2 coefficient (-1) (b)

 

Question 3:

Subtract 3a – 7ab + 48 from 90 – 6ba + 52

(a) 6a + ab + 4

(b) 6a + 3ab

(c) 6a + 3

(d) 8a + 3ab

Ans:

 

Question 4:

Substract 3x2 + 4y2 + 6xy from 9x2 + 12y2 + 8xy

(a) 6x2 + 8y2 + 2xy

(b) 3x2 + 5xy

(c) 5y2 + 6xb 

(d) 6y2 + 8x2

Ans:

 

Question 5:

Multiply 3 ab x 4ab =?

(a) 7ab2

(b) 12a2b

(c) 12ab2

(d) 12a2 b2

Ans:

3ab × 4ab = 12a2 b2 (d)

 

Question 6:

Add 4xy + 6x2y + 8xy2 with 8xy – 6x2y

(a) 3xy2

(b) 5x2 + 2

(c) 8xy + 12

(d) 12xy + 8xy2

Ans:

 

Question 7:

Product of 7q × 0.

(a) 7q

(b) 7q2

(c) 0

(d) 7

Ans:

7q × 0 = 0 when we multiply any term with zero then we get only 0.

Question 8:

Find the product of P2, q2, p2q2

(a) p4 q4

(b) p3 q3

(c) p2 q2

(d) 0

Ans:

p2 × q2 × p2 × q2

p × p × q × q × p × p × q x q = p4 × q2

= p4q4 (a)

 

Question 9:

Obtain the volume of rectangle boxes with length, breadth and height are.

6a, 3b2, 7a4

(a) 15a3 b5

(b) 216 b3

(c) 126 a5 b2

(d) 17a2 b3

Ans:

6a × 3b2 × 7a2

= 6 × a × 3 × b × b × 7 × a × a

= 126 a5 b2 (c)

 

Question 10:

Simplify 4 x (8x – 5) + 4 find its value for x = 2

(a) 90

(b) 92

(c) 82

(d) 84

Ans:

= 4x (8x – 5) + 4 for x = 2

= 4 × 2 (8 × 2 – 5) + 4

= 8 (16 – 5) + 4

= 88 + 4

= 92 (b)

 

 

Question 13:

Using identities evaluate 982

(a) 99604

(b) 99607

(c) 99609

(d) 99611

Ans:

982 = (100 – 2)2 = 1002 – 2 × 100 × 2 + 22

= 10000 – 400 + 4

= 99604

 

Question 14

Using (x + a) (x + b) = x2 + (a + b) x + ab  

Find 6.2 × 6.3

(a) 3.906

(b) 39.6 

(c) 39.0

(d) 0.396

Ans:

(x + a) (x + b)

= x2 + (a + b) x + ab

= (6 + 0.2) (6 + 0.3)

= 62 + (0.2 + 0.3) × 6 + (0.2 × 0.3)

= 36 + (0.5) × 6 + (0.06)

= 36 + 3 + 0.06

= 39.06 (c)

 

Question 15:

Simplify (xy + yz)2 – 2xy2z

(a) x3 – y3

(b) x2 y2 + x3 + y3

(c) x2 y2 + y2 z2

(d) x2 y2 – y2 – z2

Ans:

(xy + yz)2 – 2xy2 z

= (xy)2 + 2xy × yz + (yz)2 – 2xy2z

= x2y2 + 2xy2z + y2z2 – 2xy2z

= x2y2 + y2z2 (c)

Updated: April 11, 2023 — 12:29 pm

2 Comments

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  1. Class 8 ch 9 I have one problem in this question (998)² find using identities

    1. (1000-2)²
      (1000)²+(2)²-2×1000×2 ☞(a-b)²
      1000000+4-4000
      1000004-4000
      996004 ✯✯ANSWER

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